`FeC_(2)O_(4),Fe_(2)(C_(2)O_(4))_(3),FeSO_(4),Fe_(2)(SO_(4))_(3)` one mole each, will react how many moles of `KMnO_(4)`.

In order to oxidise a mixture of one mole of each of FeC_(2)O_(4),Fe_(2)(C_(2)O_(4))_(3),FeSO_(4) and Fe_(2)(SO_(4))_(3) in acidic medium, the number of moles of KMnO_(4) required is :

In order to oxidise a mixture of one mole of each of FeC_(2)O_(4).Fe_(2)(C_(2)O_(4))_(3),FeSO_(4) and Fe_(2)(SO_(4))_(3) in acidic medium, the number of moles of KMnO_(4) required is:

Na_(3)PO_(4)+Fe_(2)(SO_(4))_(3) to FePO_(4) darr+Na_(2)SO_(4)

Fe_(3)O_(4) is:

In the reaction CrO_(5) + H_(2)SO_(4)rarr Cr_(2)(sO_(4))_(3)+H_(2)O+O_(2) , one mole of CrO_(5) will liberate how many molesof O_(2) :

FeCr_(2)O_(4)+Na_(2)CO_(3)+O_(2) to Fe_(2)O_(3)darr+Na_(2)CrO_(4)

FeCr_(2)O_(4)+Na_(2)CO_(3)+O_(2) to Fe_(2)O_(3)darr+Na_(2)CrO_(4)

Taking the example of the reaction K_(2)Cr_(2)O_(7)+H_(2)SO_(4)+FeSO_(4)toK_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+Fe_(2)(SO_(4))_(3)+H_(2)O, explain how a redox reaction is balanced by oxidation number method.

How many mole of FeSO_(4),H_(2)C_(2)O_(4) and FeC_(2)O_(4) are oxidised separately by one mole of KMnO_(4) in acid medium?

FeS+KMnO_(4)+H_(2)SO_(4)rarr Fe_(2)(SO_(4))_(3)+K_(2)SO_(4) . The equivalent mass FeS in the above reaction is :