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|{:([A],[B],"Initial Rate"),(0.05,0.05,0...

`|{:([A],[B],"Initial Rate"),(0.05,0.05,0.045),(0.10,0.05,0.09),(0.20,0.10,0.72):}|` for `2A+BtoC`. Find the rate law

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For the reaction 2A+BrarrC , the values of initial rate at different reactant concentrations are given in the table below. The rate law for the reaction is : {:([A]("mol"L^(-1)),[B]("mol"L^(-1)),{:("Initial Rate"),("mol"^(-1)s^(-1)):}),(0.05,0.05,0.045),(0.10,0.05,0.090),(0.20,0.10,0.72):}

The data for the reaction: A + B overset(k)rarr C . |{:("Experiment",[A]_(0),[B]_(0),"Initial rate"),(1,0.012,0.035,0.10),(2,0.024,0.070,0.80),(3,0.024,0.035,0.10),(4,0.012,0.070,0.80):}| The rate law corresponding to the above data is (a) Rate = k[B]^(3) , (b) Rate = k[B]^(4) ( c) Rate = k[A][B]^(3) , (d) Rate = k[A]^(2)[B]^(2)

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For the hypothetical reaction 2A + B rarr Products following data obtained: |{:("Experiment number","Initial conc of (A)" (mol L^(-1)),"Initial conc of (B)" (mol L^(-1)),"Initial rate mol" L^(-1) s^(-1),),(1,0.10,0.20,3 xx 10^(2),),(2,0.30,0.40,3.6 xx 10^(10^(3)),),(3,0.30,0.80,1.44 xx 10^(4),),(4,0.10,0.40,...,),(5,0.20,0.60,...,),(6,0.30,1.20,...,):}| Find out how the rate of the reaction depends upon the concentration of A and B and fill in the blanks given in the table.

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