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A solid sphere of radius a and mass m is...

A solid sphere of radius `a` and mass `m` is surrounded by cocentric spherical shell of thickness `2a` and mass `2m` the gravitational field at a distance 3a from their centres is

A

`(Gm)/(a^(2))`

B

`(Gm)/(3a^(2))`

C

`(Gm)/(5a^(2))`

D

`(Gm)/(4a^(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the gravitational field at a distance of \(3a\) from the center of a solid sphere of radius \(a\) and mass \(m\), which is surrounded by a concentric spherical shell of thickness \(2a\) and mass \(2m\). ### Step-by-Step Solution: 1. **Identify the Components**: - We have a solid sphere with radius \(a\) and mass \(m\). - We have a spherical shell with an outer radius of \(3a\) (since the shell has a thickness of \(2a\)) and mass \(2m\). 2. **Gravitational Field due to the Solid Sphere**: - For a solid sphere, the gravitational field \(E\) at a distance \(r\) from the center (where \(r > a\)) is given by the formula: \[ E_{\text{sphere}} = \frac{Gm}{r^2} \] - Here, we are interested in the gravitational field at \(r = 3a\): \[ E_{\text{sphere}} = \frac{Gm}{(3a)^2} = \frac{Gm}{9a^2} \] 3. **Gravitational Field due to the Spherical Shell**: - For a spherical shell, the gravitational field outside the shell (where \(r > R\), \(R\) being the outer radius of the shell) is given by: \[ E_{\text{shell}} = \frac{G M_{\text{shell}}}{r^2} \] - The mass of the shell is \(2m\) and at \(r = 3a\): \[ E_{\text{shell}} = \frac{G(2m)}{(3a)^2} = \frac{2Gm}{9a^2} \] 4. **Total Gravitational Field**: - The total gravitational field at a distance \(3a\) from the center is the sum of the gravitational fields due to the solid sphere and the shell: \[ E_{\text{total}} = E_{\text{sphere}} + E_{\text{shell}} = \frac{Gm}{9a^2} + \frac{2Gm}{9a^2} \] - Combining these gives: \[ E_{\text{total}} = \frac{Gm + 2Gm}{9a^2} = \frac{3Gm}{9a^2} = \frac{Gm}{3a^2} \] 5. **Final Answer**: - Therefore, the gravitational field at a distance \(3a\) from the center is: \[ E_{\text{total}} = \frac{Gm}{3a^2} \] ### Conclusion: The gravitational field at a distance \(3a\) from the center is \(\frac{Gm}{3a^2}\).
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