Arrange in the increasing order of oxidation state of nitrogen for following nitrogen oxides `N_(2)O, NO_(2), NO, N_(2)O_(3)`

Options

A. `N_(2)OltNOltNO_(2)ltN_(2)O_(3)`
B. `NOltN_(2)OltN_(2)OltN_(2)O_(3)ltNO_(2)`
C. `N_(2)OltNOltN_(2)O_(3)ltNO_(2)`
D. `NO_(2)ltN_(2)O_(3)ltN_(2)OltNO`

Answer

To find the increasing order of oxidation states of nitrogen in the nitrogen oxides \(N_2O\), \(NO_2\), \(NO\), and \(N_2O_3\), we will calculate the oxidation state of nitrogen in each compound step by step.

### Step 1: Calculate the oxidation state of nitrogen in \(N_2O\)

1. Assume the oxidation state of nitrogen is \(x\).
2. The oxidation state of oxygen is \(-2\).
3. The overall charge of the compound is 0 (neutral compound).
4. Set up the equation:
\[ 2x + (-2) = 0 \]
5. Solve for \(x\):
\[ 2x - 2 = 0 \implies 2x = 2 \implies x = +1 \]
So, the oxidation state of nitrogen in \(N_2O\) is \(+1\).

### Step 2: Calculate the oxidation state of nitrogen in \(NO_2\)

1. Assume the oxidation state of nitrogen is \(x\).
2. The oxidation state of oxygen is \(-2\).
3. The overall charge of the compound is 0.
4. Set up the equation:
\[ x + 2(-2) = 0 \]
5. Solve for \(x\):
\[ x - 4 = 0 \implies x = +4 \]
So, the oxidation state of nitrogen in \(NO_2\) is \(+4\).

### Step 3: Calculate the oxidation state of nitrogen in \(NO\)

1. Assume the oxidation state of nitrogen is \(x\).
2. The oxidation state of oxygen is \(-2\).
3. The overall charge of the compound is 0.
4. Set up the equation:
\[ x + (-2) = 0 \]
5. Solve for \(x\):
\[ x - 2 = 0 \implies x = +2 \]
So, the oxidation state of nitrogen in \(NO\) is \(+2\).

### Step 4: Calculate the oxidation state of nitrogen in \(N_2O_3\)

1. Assume the oxidation state of nitrogen is \(x\).
2. The oxidation state of oxygen is \(-2\).
3. The overall charge of the compound is 0.
4. Set up the equation:
\[ 2x + 3(-2) = 0 \]
5. Solve for \(x\):
\[ 2x - 6 = 0 \implies 2x = 6 \implies x = +3 \]
So, the oxidation state of nitrogen in \(N_2O_3\) is \(+3\).

### Step 5: Arrange the oxidation states in increasing order

Now we have the oxidation states of nitrogen in each compound:
- \(N_2O\): \(+1\)
- \(NO\): \(+2\)
- \(N_2O_3\): \(+3\)
- \(NO_2\): \(+4\)

Arranging these in increasing order:
1. \(N_2O\) (\(+1\))
2. \(NO\) (\(+2\))
3. \(N_2O_3\) (\(+3\))
4. \(NO_2\) (\(+4\))

### Final Answer

The increasing order of oxidation states of nitrogen in the given nitrogen oxides is:
\[ N_2O < NO < N_2O_3 < NO_2 \]