Which of the following will show optical activity

Options

A.
B.
C.
D.

Answer

To determine which of the given compounds shows optical activity, we need to analyze each compound for the presence of a plane of symmetry. A compound is optically active if it lacks a plane of symmetry, while the presence of a plane of symmetry indicates that the compound is optically inactive.

### Step-by-Step Solution:

1. **Identify the Compounds:**
We have four coordination complexes to analyze for optical activity.

2. **Analyze the First Compound:**
- Check for a plane of symmetry.
- The first compound has no plane of symmetry.
- **Conclusion:** This compound is optically active.

3. **Analyze the Second Compound:**
- This compound is identified as a facial (FAC) isomer.
- Facial isomers typically have a plane of symmetry.
- **Conclusion:** This compound is optically inactive.

4. **Analyze the Third Compound:**
- Check for a plane of symmetry.
- The third compound has a vertical plane of symmetry that divides it into two equal halves.
- **Conclusion:** This compound is optically inactive.

5. **Analyze the Fourth Compound:**
- Check for a plane of symmetry.
- The fourth compound also has a diagonal plane of symmetry.
- **Conclusion:** This compound is optically inactive.

6. **Final Conclusion:**
- Only the first compound is optically active due to the absence of a plane of symmetry. The other three compounds are optically inactive because they have planes of symmetry.

### Answer:
The first compound is the only one that shows optical activity.

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