Home
Class 12
PHYSICS
A uniform rod of mass M and length L hig...


A uniform rod of mass `M` and length `L` highed at centre is rotating in horizontal plane with angular speed `omega_(0)` now two object each of mass `m` are kept on rod near thhe hinge on both sides. They starts sliding towards ends. Find `omega` of rod finally

A

`(Momega_(0))/(6M+m)`

B

`(Momega_(0))/(M+6m)`

C

`(6Momega_(0))/(M+m)`

D

`(Momega_(0))/(M+2m)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • JEE MAINS

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise Chemistry|1 Videos

  • JEE MAIN

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise All Questions|452 Videos

  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise PHYSICS|250 Videos

Similar Questions

Explore conceptually related problems

A uniform rod of mass m and length l rotates in a horizontal plane with an angular velocity omega about a vertical axis passing through one end. The tension in the rod at a distance x from the axis is

A uniform of mass m and length L is tied to a vertical shaft. It rotates in horizontal plane about the vertical axis at angular velocity omega . How much horizontal force does the shaft exert on the rod?

A uniform rod of mass m and length L lies radialy on a disc rotating with angular speed omega in a horizontal plane about vertical axis passing thorugh centre of disc. The rod does not slip on the disc and the centre of the rod is at a distance 2L from the centre of the disc. them the kinetic energy of the rod is

A thin uniform rod of length l and mass m is swinging freely about a horizontal axis passing through its end. Its maximum angular speed is omega . Its centre of mass rises to a maximum height of -

A uniform rod of mass m and length L is hinged at one end and free to rotate in the horizontal plane. All the surface are smooth. A particle of same mass m collides with the rod with a speed V_(0) . The coefficient of restitution for the collision is e=(1)/(2) . If hinge reaction during the collision is zero then the value of x is :

A uniform rod of mass 20 Kg and length 1.6 m is piovted at its end and swings freely in the vertical plane. Angular acceleration of the rod just after the rod is relased from rest in the horizontal position is

A rod AB of mass m and length L is rotating in horizontal plane about one of its ends which is pivoted. The constant angular speed with which the rod is rotating is omega . The force applied on the rod by the pivot is

A uniform rod of mass m and length L is free to rotate in the vertical plane about a horizontal axis passing through its end. The rod initially in horizontal position is released. The initial angular acceleration of the rod is:

A rod PQ of mass M and length L is hinged at end P. The rod is kept horizontal by a massless string tied to point Q as shown in figure. When string is cut, the intial angular acceleration of the rod is

A rod of mass 2 kg ad length 2 m is rotating about its one end O with an angular velocity omega=4rad//s . Find angular momentum of the rod about the axis rotation.