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Current passing through galvanometer is ...

Current passing through galvanometer is 0.002A and resistance of galvanometer is `R_(g)=50Omega` find out shunt resistance to convert it into ammeter of range 0.5 A

A

`0.5Omega`

B

`0.2Omega`

C

`0.7Omega`

D

`0.9Omega`

Text Solution

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The correct Answer is:
To solve the problem of finding the shunt resistance required to convert a galvanometer into an ammeter with a specific range, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Values**: - Current through the galvanometer, \( I_G = 0.002 \, \text{A} \) - Resistance of the galvanometer, \( R_G = 50 \, \Omega \) - Desired range of the ammeter, \( I = 0.5 \, \text{A} \) 2. **Understand the Concept of Shunt Resistance**: - To convert a galvanometer into an ammeter, a shunt resistance \( R_S \) is connected in parallel with the galvanometer. The shunt allows most of the current to bypass the galvanometer, while a small portion still passes through it. 3. **Use the Formula for Shunt Resistance**: - The formula for shunt resistance \( R_S \) is given by: \[ R_S = \frac{I_G \cdot R_G}{I - I_G} \] - Where: - \( I_G \) is the current through the galvanometer, - \( R_G \) is the resistance of the galvanometer, - \( I \) is the total current passing through the ammeter. 4. **Substitute Given Values into the Formula**: - Substitute \( I_G = 0.002 \, \text{A} \), \( R_G = 50 \, \Omega \), and \( I = 0.5 \, \text{A} \): \[ R_S = \frac{0.002 \cdot 50}{0.5 - 0.002} \] 5. **Calculate the Denominator**: - Calculate \( 0.5 - 0.002 = 0.498 \). 6. **Calculate the Numerator**: - Calculate \( 0.002 \cdot 50 = 0.1 \). 7. **Final Calculation**: - Now substitute back into the formula: \[ R_S = \frac{0.1}{0.498} \approx 0.2004 \, \Omega \] - Rounding to two decimal places, we find: \[ R_S \approx 0.2 \, \Omega \] 8. **Conclusion**: - The required shunt resistance to convert the galvanometer into an ammeter of range 0.5 A is \( R_S = 0.2 \, \Omega \).
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