`m_(1)` gram of ice at `-10^(@)C` and `m_(2)` gram of water at `50^(@)C` are mixed in insulated container. If in equilibrium state we get only water at `0^(@)C` then latent heat of ice is :
A
`(50m_(2))/(m_(1))+5`
B
`(50m_(2))/(m_(1))-5`
C
`(50m_(2))/(m_(1))+50`
D
`(50m_(2))/(m_(1))-50`
Text Solution
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The correct Answer is:
B
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