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A spring of length 'l' has spring consta...

A spring of length `'l'` has spring constant `'k'` is cut into two parts of length `l_(1)` and `l_(2)`. If their respective spring constahnt are `K_(1)` and `k_(2)`, then `(K_(1))/(K_(2))` is:

A

`(l_(2))/(l_(1))`

B

`(2l_(2))/(l_(1))`

C

`(l_(1))/(l_(2))`

D

None

Text Solution

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The correct Answer is:
To solve the problem, we need to find the ratio of the spring constants \( K_1 \) and \( K_2 \) of two parts of a spring that has been cut into lengths \( l_1 \) and \( l_2 \). ### Step-by-Step Solution: 1. **Understanding the Problem**: - We have a spring of total length \( l \) and spring constant \( k \). - The spring is cut into two parts: one of length \( l_1 \) and the other of length \( l_2 \). - We need to find the ratio \( \frac{K_1}{K_2} \) where \( K_1 \) is the spring constant of the first part and \( K_2 \) is the spring constant of the second part. 2. **Using the Spring Constant Formula**: - The spring constant of a spring is inversely proportional to its length. This means: \[ K \propto \frac{1}{l} \] - Therefore, if we have two parts of the spring, we can express their spring constants as: \[ K_1 = \frac{k \cdot l}{l_1} \quad \text{and} \quad K_2 = \frac{k \cdot l}{l_2} \] 3. **Setting Up the Ratio**: - Now, we can find the ratio of the spring constants \( K_1 \) and \( K_2 \): \[ \frac{K_1}{K_2} = \frac{\frac{k \cdot l}{l_1}}{\frac{k \cdot l}{l_2}} \] 4. **Simplifying the Ratio**: - The \( k \) and \( l \) terms cancel out: \[ \frac{K_1}{K_2} = \frac{l_2}{l_1} \] 5. **Final Answer**: - Thus, the ratio of the spring constants is: \[ \frac{K_1}{K_2} = \frac{l_2}{l_1} \]
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