A spring of length `'l'` has spring constant `'k'` is cut into two parts of length `l_(1)` and `l_(2)`. If their respective spring constahnt are `K_(1)` and `k_(2)`, then `(K_(1))/(K_(2))` is:
A
`(l_(2))/(l_(1))`
B
`(2l_(2))/(l_(1))`
C
`(l_(1))/(l_(2))`
D
None
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem, we need to find the ratio of the spring constants \( K_1 \) and \( K_2 \) of two parts of a spring that has been cut into lengths \( l_1 \) and \( l_2 \).
### Step-by-Step Solution:
1. **Understanding the Problem**:
- We have a spring of total length \( l \) and spring constant \( k \).
- The spring is cut into two parts: one of length \( l_1 \) and the other of length \( l_2 \).
- We need to find the ratio \( \frac{K_1}{K_2} \) where \( K_1 \) is the spring constant of the first part and \( K_2 \) is the spring constant of the second part.
2. **Using the Spring Constant Formula**:
- The spring constant of a spring is inversely proportional to its length. This means:
\[
K \propto \frac{1}{l}
\]
- Therefore, if we have two parts of the spring, we can express their spring constants as:
\[
K_1 = \frac{k \cdot l}{l_1} \quad \text{and} \quad K_2 = \frac{k \cdot l}{l_2}
\]
3. **Setting Up the Ratio**:
- Now, we can find the ratio of the spring constants \( K_1 \) and \( K_2 \):
\[
\frac{K_1}{K_2} = \frac{\frac{k \cdot l}{l_1}}{\frac{k \cdot l}{l_2}}
\]
4. **Simplifying the Ratio**:
- The \( k \) and \( l \) terms cancel out:
\[
\frac{K_1}{K_2} = \frac{l_2}{l_1}
\]
5. **Final Answer**:
- Thus, the ratio of the spring constants is:
\[
\frac{K_1}{K_2} = \frac{l_2}{l_1}
\]
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