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In isobaric process of ideal gas (f=5) w...

In isobaric process of ideal gas `(f=5)` work done by gas is equal of `10J`. Then heat given to gas during process:

A

`25J`

B

`15J`

C

`45J`

D

`35J`

Text Solution

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The correct Answer is:
To find the heat given to the gas during an isobaric process, we can use the relationship between work done, heat, and the degrees of freedom of the gas. ### Step-by-Step Solution: 1. **Identify the Given Values**: - Work done by the gas, \( W = 10 \, \text{J} \) - Degrees of freedom, \( f = 5 \) 2. **Understand the Isobaric Process**: - In an isobaric process, the pressure remains constant. The relationship between heat added to the system (\( Q \)), work done by the system (\( W \)), and the change in internal energy (\( \Delta U \)) is given by: \[ Q = \Delta U + W \] 3. **Relate Internal Energy Change to Degrees of Freedom**: - For an ideal gas, the change in internal energy (\( \Delta U \)) can be expressed in terms of the degrees of freedom: \[ \Delta U = \frac{f}{2} n R \Delta T \] - However, we can also relate \( Q \) directly to \( W \) using the specific heat capacity at constant pressure, which is related to degrees of freedom. 4. **Calculate the Heat Transfer**: - The relationship between heat transfer and work done in an isobaric process is given by: \[ Q = \frac{f + 2}{f} W \] - Substituting the values: \[ Q = \frac{5 + 2}{5} \times 10 \, \text{J} \] \[ Q = \frac{7}{5} \times 10 \, \text{J} = 14 \, \text{J} \] 5. **Final Calculation**: - Since we need to find the heat given to the gas, we can also use the formula: \[ Q = \frac{7}{2} W \] - Substituting \( W = 10 \, \text{J} \): \[ Q = \frac{7}{2} \times 10 = 35 \, \text{J} \] ### Conclusion: The heat given to the gas during the isobaric process is \( Q = 35 \, \text{J} \).
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