25g of an unknown hydrocarbon upon burning produces 88g of `CO_(2)` and 9 g of `H_(2)O`. This unknown hydrocarbon contains:
A
`C=24g,H=1g`
B
`C=20g,H=5g`
C
`C=18g,H=7g`
D
`C=19g,H=6g`
Text Solution
Verified by Experts
The correct Answer is:
A
Topper's Solved these Questions
JEE MAINS
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise QUESTION|1 Videos
JEE MAIN
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise CHEMISTRY|146 Videos
JEE MAINS 2020
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise CHEMSITRY|23 Videos
Similar Questions
Explore conceptually related problems
25 g of an unknown hydrocarbon upon burning produces 88 g of CO_2 and 9 g of H_2O . This unknown hydrocarbon contains
4.4 gms of a hydrocarbon on complete combustion produced 13.2 gms of CO_(2) and 7.2 gms of H_(2)O . What is the hydrocarbon?
10 ml of gaseous hydrocarbon on combution gives 20ml of CO_(2) and 30ml of H_(2)O(g) . The hydrocarbon is :-
25 g hydrocarbon of burning with excess of air produces 88 g CO_(2) and 9g water, mass of C and H in the hydrocarbon is
3g of a hydrocarbons on combusion in excess of oxygen produces 8.8g of CO_(2) and 5.4g of H_(2)O . The data illustrates the law of:
10mL of gaseous hydrocarbon on combustion gives 40ml of CO_(2)(g) and 50mL of H_(2)O (vapour) The hydrocarbon is .
6g of a hydrocarbon on combustion in excess of oxygen produces 17.6g of CO_(2) and 10.8g of H_(2)O . The data illustrates the law of :
4.4 gms of a hydrocarbon on complete combustion produced 13.2 gms of CO_(2) and 7.2 gms of H_(2)O . How many moles of oxygen is consumed per mole of hydrocarbon in the combustion?
How much oxygen is formed from 264 g of CO_(2) and 216 g of H_(2)O ?
25 g of an unknown hydrocarbon contains 24 g of carbon. 25 g of this hydrocarbon on burning produces x gm of H_(2)O . The numerical value of x is_____.
JEE MAINS PREVIOUS YEAR ENGLISH-JEE MAINS-QUESTION