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A circular coil having N turns and radiu...

A circular coil having N turns and radius r carries a current I. It is held in the XZ plane in a magnetic field `Bhati`. The torque on the coil due to the magnetic field is :

A

`(Br^(2)I)/(piN)`

B

`Bpir^(2)IN`

C

`(Bpir^(2)(I))/(N)`

D

Zero

Text Solution

AI Generated Solution

The correct Answer is:
To find the torque on a circular coil placed in a magnetic field, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Parameters:** - Number of turns of the coil, \( N \) - Radius of the coil, \( r \) - Current flowing through the coil, \( I \) - Magnetic field, \( \mathbf{B} = B \hat{i} \) (along the x-direction) 2. **Determine the Area of the Coil:** The area \( A \) of a circular coil is given by the formula: \[ A = \pi r^2 \] 3. **Calculate the Magnetic Moment \( \mathbf{m} \):** The magnetic moment \( \mathbf{m} \) of the coil is given by: \[ \mathbf{m} = N \cdot I \cdot A \] Substituting the area \( A \): \[ \mathbf{m} = N \cdot I \cdot (\pi r^2) \] 4. **Determine the Direction of the Magnetic Moment:** Since the coil is in the xz-plane, the area vector \( \mathbf{A} \) (and hence the magnetic moment \( \mathbf{m} \)) will be perpendicular to the plane of the coil. Therefore, it points in the y-direction: \[ \mathbf{m} = N \cdot I \cdot \pi r^2 \hat{j} \] 5. **Calculate the Torque \( \mathbf{\tau} \):** The torque \( \mathbf{\tau} \) on the coil in a magnetic field is given by the cross product: \[ \mathbf{\tau} = \mathbf{m} \times \mathbf{B} \] Substituting the values of \( \mathbf{m} \) and \( \mathbf{B} \): \[ \mathbf{\tau} = (N \cdot I \cdot \pi r^2 \hat{j}) \times (B \hat{i}) \] 6. **Evaluate the Cross Product:** Using the right-hand rule and the properties of cross products: \[ \mathbf{\tau} = N \cdot I \cdot \pi r^2 \cdot B (\hat{j} \times \hat{i}) \] Since \( \hat{j} \times \hat{i} = -\hat{k} \), we have: \[ \mathbf{\tau} = -N \cdot I \cdot \pi r^2 \cdot B \hat{k} \] 7. **Magnitude of the Torque:** The magnitude of the torque is: \[ |\mathbf{\tau}| = N \cdot I \cdot \pi r^2 \cdot B \] ### Final Result: The torque on the coil due to the magnetic field is: \[ |\mathbf{\tau}| = N \cdot I \cdot \pi r^2 \cdot B \]
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