Diborane `(B_(2)H_(6))` reacts independently with `O_(2)` and `H_(2)O` to produce, respectively:

Options

A. `B_(2)O_(3)` and `H_(3)BO_(3)`
B. `B_(2)O_(3)` and `[BH_(4)]^(-)`
C. `H_(3)BO_(3)` and `B_(2)O_(3)`
D. `HBO_(2)`and `H_(3)BO_(3)`

Answer

To solve the question regarding the reactions of diborane `(B2H6)` with `O2` and `H2O`, we will break down the reactions step by step.

### Step 1: Reaction of Diborane with Oxygen
1. **Write the reaction**: Diborane `(B2H6)` reacts with oxygen `(O2)`.
\[ B_2H_6 + O_2 \rightarrow B_2O_3 + H_2O \]
2. **Identify the products**: The primary product formed is boron oxide, which is also known as boric anhydride `(B2O3)`. Additionally, water `(H2O)` is produced as a by-product.

### Step 2: Reaction of Diborane with Water
1. **Write the reaction**: Diborane `(B2H6)` reacts with water `(H2O)`.
\[ B_2H_6 + H_2O \rightarrow H_3BO_3 \]
2. **Identify the product**: The product formed in this reaction is orthoboric acid, commonly referred to as boric acid `(H3BO3)`.

### Final Summary of Products
- When diborane reacts with oxygen, it produces boron oxide `(B2O3)` and water `(H2O)`.
- When diborane reacts with water, it produces orthoboric acid `(H3BO3)`.

### Conclusion
Thus, the products of the reactions of diborane `(B2H6)` with `O2` and `H2O` are:
1. **With O2**: Boron oxide `(B2O3)` and water `(H2O)`.
2. **With H2O**: Orthoboric acid `(H3BO3)`.