To solve the question regarding the treatment of maltose with dilute HCl, we will follow these steps:
### Step 1: Understand the Structure of Maltose
Maltose is a disaccharide composed of two glucose units linked by a glycosidic bond. The molecular formula of maltose is C12H22O11.
### Step 2: Identify the Reaction
When maltose is treated with dilute hydrochloric acid (HCl), it undergoes hydrolysis. Hydrolysis is a reaction where water is used to break down a compound. In this case, the glycosidic bond between the two glucose units in maltose will be broken.
### Step 3: Write the Hydrolysis Reaction
The hydrolysis of maltose can be represented as follows:
\[ \text{Maltose} + \text{H}_2\text{O} \xrightarrow{\text{dilute HCl}} 2 \text{Glucose} \]
### Step 4: Identify the Products
The products of the hydrolysis of maltose are two molecules of D-glucose. Each glucose molecule has the formula C6H12O6.
### Step 5: Conclusion
Thus, the final products of the reaction of maltose with dilute HCl are two molecules of glucose.
### Final Answer
Maltose on treatment with dilute HCl gives two molecules of D-glucose.
---
Topper's Solved these Questions
JEE MAINS
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise QUESTION|1 Videos
JEE MAIN
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise CHEMISTRY|146 Videos
JEE MAINS 2020
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise CHEMSITRY|23 Videos
Similar Questions
Explore conceptually related problems
An aqueous solution of a substance, on treatment with dilute HCl, gives a white precipitate soluble in hot water. When H_(2)S is passed through the hot acidic solution, a black precipitate is formed. The substance is:
A salt on treatment with dil. HCl gives a pungent smelling gas and a yellow precipitate. The salt gives green flame when tested. The solution gives a yellow ppt. with potassium chromate. The salt is
A salt on treatment with dil. HCl gives a pungent smelling gas and a yellow precipitate. The salt gives green flame when tested. The solution gives a yellow ppt. with potassium chromate. The salt is
(B) on treatment with Zn//HCl gives :
An aqueous solution of a white salt A gives a white precipitate B on treatment with dilute HCl in cold condition. B is soluble in boiling water. An aqeous solution of A gives a yellow precipitate on treatment with a solution of K_(2)CrO_(4) . The soda extract of A is acidified with diolute H_(2)SO_(4) , boiled to remove CO_(2) and treated with a freshly prepared solution of FeSO_(4) . concentratd H_(2)SO_(4) is added to the resulting solution. a brownn ring is formed at the junction of the two layers. Q. The salt A is:
An aqueous solution of a white salt A gives a white precipitate B on treatment with dilute HCl in cold condition. B is soluble in boiling water. An aqeous solution of A gives a yellow precipitate on treatment with a solution of K_(2)CrO_(4) . The soda extract of A is acidified with diolute H_(2)SO_(4) , boiled to remove CO_(2) and treated with a freshly prepared solution of FeSO_(4) . concentratd H_(2)SO_(4) is added to the resulting solution. a brownn ring is formed at the junction of the two layers. Q. On treatment with a KI solution, an aqueous solution of A will give:
Write true or false. Acetaldehyde undergoes Cannizzaro's reaction on treatment with dilute alkali.
Benzamide on treatment with POCl_3 gives :
JEE MAINS PREVIOUS YEAR ENGLISH-JEE MAINS-QUESTION