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0.27 g of a long chain fatty acid was d...

0.27 g of a long chain fatty acid was dissolved in `100cm^(3)` of hexane. `10ml` of this solution was added dropwise to the surface of water in a round watch glass . Hexane evaporates and a monolayeer is formed. The distance from edge to center of the watch glass is `10 cm` . What is the height of the monolayers?
`["Density of fatty acid "=0.9 g cm^(-3),pi=3]`

A

`10^(-6)`m

B

`10^(-8)`

C

`10^(-2)`m

D

`10^(-4)`m

Text Solution

Verified by Experts

The correct Answer is:
A
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