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If 'M' is the mass of water that rises i...

If 'M' is the mass of water that rises in a capillary tube of radius 'r', then mass of water which will ris in a capillary tube of radius '2r' is :

A

M

B

`(M)/(2)`

C

`4 M`

D

`2 M`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the relationship between the mass of water that rises in a capillary tube and the radius of the tube. Here's a step-by-step solution: ### Step 1: Understand the relationship between height and radius The height of a liquid column \( h \) that rises in a capillary tube is given by the formula: \[ h = \frac{2t \cos \theta}{\rho r g} \] where: - \( t \) is the surface tension, - \( \theta \) is the angle of contact, - \( \rho \) is the density of the liquid, - \( r \) is the radius of the tube, - \( g \) is the acceleration due to gravity. From this formula, we can see that the height \( h \) is inversely proportional to the radius \( r \): \[ h \propto \frac{1}{r} \] ### Step 2: Relate the heights for different radii Let’s denote: - \( r_1 = r \) (the radius of the first tube), - \( h_1 = h \) (the height of water in the first tube), - \( r_2 = 2r \) (the radius of the second tube). Using the inverse relationship: \[ \frac{h_1}{h_2} = \frac{r_2}{r_1} = \frac{2r}{r} = 2 \] This implies: \[ h_2 = \frac{h_1}{2} = \frac{h}{2} \] ### Step 3: Calculate the mass of water in the capillary tubes The mass of water \( M \) that rises in a capillary tube can be expressed as: \[ M = \text{Volume} \times \text{Density} \] The volume \( V \) of the water column in a cylindrical tube is given by: \[ V = \pi r^2 h \] Thus, for the first tube: \[ M_1 = \pi r^2 h \cdot \rho \] For the second tube with radius \( 2r \) and height \( h_2 = \frac{h}{2} \): \[ M_2 = \pi (2r)^2 \left(\frac{h}{2}\right) \cdot \rho \] Calculating \( M_2 \): \[ M_2 = \pi (4r^2) \left(\frac{h}{2}\right) \cdot \rho = 2 \cdot \pi r^2 h \cdot \rho = 2M \] ### Conclusion Thus, the mass of water that rises in a capillary tube of radius \( 2r \) is: \[ M_2 = 2M \] ### Final Answer The mass of water that will rise in a capillary tube of radius \( 2r \) is \( 2M \).
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