The correct order of the oxidation states of nitrogen in `NO, N_(2)O, NO_(2)` and `N_(2)O_(3)` is :

Options

A. `NO_(2)ltNOltN_(2)O_(3)ltN_(2)O`
B. `NO_(2)ltN_(2)O_(3)ltNOltN_(2)O`
C. `N_(2)OltN_(2)O_(3)ltNOltNO_(2)`
D. `N_(2)OltNOltN_(2)O_(3)ltNO_(2)`

Answer

To determine the correct order of the oxidation states of nitrogen in the compounds NO, N2O, NO2, and N2O3, we will calculate the oxidation state of nitrogen in each compound step by step.

### Step 1: Calculate the oxidation state of nitrogen in NO
1. Let the oxidation state of nitrogen be \( X \).
2. The oxidation state of oxygen is \( -2 \).
3. The compound is neutral, so we set up the equation:
\[ X + (-2) = 0 \]
4. Solving for \( X \):
\[ X - 2 = 0 \implies X = +2 \]
Therefore, the oxidation state of nitrogen in NO is **+2**.

### Step 2: Calculate the oxidation state of nitrogen in N2O
1. In N2O, there are 2 nitrogen atoms, so let the oxidation state of nitrogen be \( X \).
2. The oxidation state of oxygen is \( -2 \).
3. The equation for the compound is:
\[ 2X + (-2) = 0 \]
4. Solving for \( X \):
\[ 2X - 2 = 0 \implies 2X = 2 \implies X = +1 \]
Therefore, the oxidation state of nitrogen in N2O is **+1**.

### Step 3: Calculate the oxidation state of nitrogen in NO2
1. For NO2, let the oxidation state of nitrogen be \( X \).
2. There are 2 oxygen atoms, so the equation is:
\[ X + 2(-2) = 0 \]
3. Solving for \( X \):
\[ X - 4 = 0 \implies X = +4 \]
Therefore, the oxidation state of nitrogen in NO2 is **+4**.

### Step 4: Calculate the oxidation state of nitrogen in N2O3
1. In N2O3, there are 2 nitrogen atoms, so let the oxidation state of nitrogen be \( X \).
2. There are 3 oxygen atoms, so the equation is:
\[ 2X + 3(-2) = 0 \]
3. Solving for \( X \):
\[ 2X - 6 = 0 \implies 2X = 6 \implies X = +3 \]
Therefore, the oxidation state of nitrogen in N2O3 is **+3**.

### Step 5: Arrange the oxidation states in order
Now we have the oxidation states of nitrogen in each compound:
- NO: +2
- N2O: +1
- NO2: +4
- N2O3: +3

Arranging these in order from highest to lowest:
1. NO2: +4
2. N2O3: +3
3. NO: +2
4. N2O: +1

Thus, the correct order of the oxidation states of nitrogen in NO, N2O, NO2, and N2O3 is:
**NO2 > N2O3 > NO > N2O**.

### Final Answer:
The correct order of the oxidation states of nitrogen is: **NO2 (+4) > N2O3 (+3) > NO (+2) > N2O (+1)**.