The number of water molecule(s) not coordinated to copper ion directly in `CuSO_(4).5H_(2)O`, is :

Options

A. 2
B. 3
C. 1
D. 4

Answer

To determine the number of water molecules not coordinated to the copper ion in `CuSO4.5H2O`, we can follow these steps:

### Step 1: Understand the Composition of `CuSO4.5H2O`
`CuSO4.5H2O` is a hydrated copper(II) sulfate compound. It consists of one copper ion (Cu²⁺), one sulfate ion (SO₄²⁻), and five water molecules (H₂O).

### Step 2: Identify the Coordination of Water Molecules
In the complex, the copper ion (Cu²⁺) can coordinate with water molecules. Coordination means that the water molecules are directly bonded to the copper ion through their lone pairs of electrons.

### Step 3: Determine the Number of Coordinated Water Molecules
In the case of `CuSO4.5H2O`, it is known that typically four water molecules coordinate directly to the copper ion. This is a common coordination number for copper(II) complexes.

### Step 4: Calculate the Non-Coordinated Water Molecules
Since there are a total of five water molecules and four of them are coordinated to the copper ion, we can find the number of water molecules that are not coordinated by subtracting the number of coordinated water molecules from the total number of water molecules:

Total water molecules = 5
Coordinated water molecules = 4
Non-coordinated water molecules = Total water molecules - Coordinated water molecules
Non-coordinated water molecules = 5 - 4 = 1

### Conclusion
Thus, the number of water molecules not coordinated to the copper ion in `CuSO4.5H2O` is **1**.