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Diameter of the objective lens of a tele...

Diameter of the objective lens of a telescope is 250 cm. For light of wavelength 600 nm coming from a distance object, the limit of resolution of the telescope is close to :

A

`1.5xx10^(-7) rad`

B

`2.0xx10^(-7) rad`

C

`3.0xx10^(-7) rad`

D

`4.5xx10^(-7) rad`

Text Solution

AI Generated Solution

The correct Answer is:
To find the limit of resolution of a telescope, we can use the formula: \[ \text{Limit of Resolution} (R) = \frac{1.22 \lambda}{d} \] where: - \( \lambda \) is the wavelength of light, - \( d \) is the diameter of the objective lens. ### Step-by-Step Solution: 1. **Identify the given values:** - Diameter of the objective lens, \( d = 250 \, \text{cm} \) - Wavelength of light, \( \lambda = 600 \, \text{nm} \) 2. **Convert the units:** - Convert the diameter from centimeters to meters: \[ d = 250 \, \text{cm} = 250 \times 10^{-2} \, \text{m} = 2.5 \, \text{m} \] - Convert the wavelength from nanometers to meters: \[ \lambda = 600 \, \text{nm} = 600 \times 10^{-9} \, \text{m} = 6.0 \times 10^{-7} \, \text{m} \] 3. **Substitute the values into the resolution formula:** \[ R = \frac{1.22 \times 6.0 \times 10^{-7}}{2.5} \] 4. **Calculate the numerator:** \[ 1.22 \times 6.0 = 7.32 \] 5. **Calculate the limit of resolution:** \[ R = \frac{7.32 \times 10^{-7}}{2.5} = 2.928 \times 10^{-7} \, \text{m} \] 6. **Round the result:** \[ R \approx 3.0 \times 10^{-7} \, \text{m} \] ### Final Answer: The limit of resolution of the telescope is approximately \( 3.0 \times 10^{-7} \, \text{m} \). ---
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