A thin convex lens L (refractive index =1.5) is placed on a plane mirror M. when a pin is placed at A, such that OA=18 cm, its real inverted image is formed at A itself, as shown in figure. when a liquid of refractive index `mu_(i)` is put between the lens and the mirror, the pin has to be removed to A',. such that OA'=27 cm, to get its inverted real image at A' itself. the value of `mu_(i)` will be
A
`(4)/(3)`
B
`(3)/(2)`
C
`sqrt(3)`
D
`sqrt(2)`
Text Solution
Verified by Experts
The correct Answer is:
A
Topper's Solved these Questions
JEE MAINS
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise Chemistry|1 Videos
JEE MAIN
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise All Questions|452 Videos
JEE MAINS 2020
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise PHYSICS|250 Videos
Similar Questions
Explore conceptually related problems
A convex lens of focal length 15 cm is placed on a plane mirror. An object is placed at 30 cm from the lens. The image is
If a convex lens of refractive index mu _l is placed in a medium of refractive index mu_m Such that mu_l > mu_m > mu_(air) then
A convex lens (refractive index mu = 1.5) has a power P. If it is immersed in a liquid ( mu = 4/3), then its power will become/remain
A convex lens is dipped in a liquid whose refractive index is equal to the refractive of the lens. Then its focal length will
A thin lens of refractive index 1.5 has focal length of 15 cm in air. When the lens is placed is a medium of refractive index (4)/(3), its focal length will become …..cm.
A thin equiconvex lens of refractive index 3//2 is placed on a horizontal plane mirror as shown in figure. The space between the lens and the mirror is filled with a liquid of refractive index 4//3 . It is found that when a point object is placed 15 cm above the lens on its priincipal axis, the object coincides with its own image. Q. The radius of curvature of the convex surface is
A thin convex lens of focal length 30 cm is placed in front of a plane mirror. An object is placed at a distance x from the lens (not in between lens and mirror ) so that its final image coincides with itself. Then, the value of x is
A double convex lens of refractive index m_(1) is immersed in a liquid of refractive index m_(2) . This lens will act as:
A convex lens of refractive index 1.5 has a focal length of 20 cm in air. Calculate the change in its focal length when it is immersed in water of refractive index 4/3.
An equiconvex lens of refractive index n_(2) is placed such that the refractive index of the surrouding media is as shown. The lens :
JEE MAINS PREVIOUS YEAR ENGLISH-JEE MAINS-Chemistry