The major product of the following reaction is : `CH_(3)overset(OH)overset(|)(C)HCH_(2)CH_(2)NH_(2)overset("ethyl formate(1 equiv.)")underset("triethylamine")rarr`
To determine the major product of the given reaction, we will analyze the substrate and the reagents step by step.
### Step 1: Identify the Substrate
The substrate is given as:
\[ \text{CH}_3-\text{C}(\text{OH})(\text{C}_2\text{H}_5)-\text{CH}_2-\text{CH}_2-\text{NH}_2 \]
This structure consists of a carbon chain with a hydroxyl group (-OH) and an amine group (-NH2).
### Step 2: Identify the Reagents
The reagents provided are:
- Ethyl formate (HCOOCH2CH3)
- Triethylamine
Ethyl formate has the structure:
\[ \text{HCOO}-\text{C}_2\text{H}_5 \]
It contains a carbonyl group (C=O) and an ethyl group.
### Step 3: Determine the Nucleophile
In this reaction, we have two potential nucleophiles: the hydroxyl group (-OH) and the amine group (-NH2). Among these, the amine group is a stronger nucleophile compared to the hydroxyl group.
### Step 4: Nucleophilic Attack
The amine group (-NH2) will attack the carbonyl carbon of ethyl formate. This leads to the formation of a tetrahedral intermediate. The reaction can be visualized as follows:
1. The nitrogen atom of the amine attacks the carbonyl carbon of ethyl formate.
2. This results in the opening of the carbonyl bond and formation of a negatively charged oxygen.
### Step 5: Collapse of the Tetrahedral Intermediate
After the formation of the tetrahedral intermediate, the negatively charged oxygen will push back to reform the carbonyl double bond, causing the ethoxy group (O-C2H5) to leave. This results in the formation of an imine (or a related structure) and the release of ethanol.
### Step 6: Final Product
The final product of the reaction will be:
\[ \text{CH}_3-\text{C}(\text{OH})(\text{C}_2\text{H}_2\text{N})-\text{C}(=O)-\text{H} \]
This structure represents an aldehyde.
### Conclusion
The major product of the reaction is an aldehyde.
### Answer:
The correct option is option B (aldehyde).
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