A particle moves in space such that its position vector varies as `vec(r)=2thati+3t^(2)hatj`. If mass of particle is 2 kg then angular momentum of particle about origin at `t=2` sec is
A
`48(hati+hatj)`
B
`36hatk`
C
`-34(hatk-hati)`
D
`48hatk`
Text Solution
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The correct Answer is:
B
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