A sound source is moving with speed `50 m//s` towards a fixed observer. Frequency observed by observer is `1000Hz`. Find out apparent frequency observed by observer when source is moving away from observer (Speed of sound `=350 m//s`)
A
750 Hz
B
857 Hz
C
1143 Hz
D
807 Hz
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem, we will use the Doppler effect formula for sound. The frequency observed by a stationary observer when the source is moving towards or away from them can be calculated using the following formulas:
1. When the source is moving towards the observer:
\[
f' = f \frac{v}{v - v_s}
\]
where:
- \( f' \) = observed frequency
- \( f \) = actual frequency of the source
- \( v \) = speed of sound
- \( v_s \) = speed of the source
2. When the source is moving away from the observer:
\[
f'' = f \frac{v}{v + v_s}
\]
where \( f'' \) is the observed frequency when the source is moving away.
### Step-by-Step Solution
**Step 1: Identify the known values.**
- Speed of sound, \( v = 350 \, \text{m/s} \)
- Speed of the source, \( v_s = 50 \, \text{m/s} \)
- Observed frequency when the source is approaching, \( f' = 1000 \, \text{Hz} \)
**Step 2: Use the first formula to find the actual frequency \( f \).**
Using the formula for the frequency when the source is moving towards the observer:
\[
f' = f \frac{v}{v - v_s}
\]
Substituting the known values:
\[
1000 = f \frac{350}{350 - 50}
\]
\[
1000 = f \frac{350}{300}
\]
\[
1000 = f \cdot \frac{7}{6}
\]
Now, solve for \( f \):
\[
f = 1000 \cdot \frac{6}{7} = \frac{6000}{7} \approx 857.14 \, \text{Hz}
\]
**Step 3: Use the second formula to find the apparent frequency \( f'' \) when the source is moving away.**
Using the formula for the frequency when the source is moving away from the observer:
\[
f'' = f \frac{v}{v + v_s}
\]
Substituting the values we have:
\[
f'' = \left(\frac{6000}{7}\right) \frac{350}{350 + 50}
\]
\[
f'' = \left(\frac{6000}{7}\right) \frac{350}{400}
\]
\[
f'' = \left(\frac{6000}{7}\right) \cdot \frac{7}{8} = \frac{6000}{8} = 750 \, \text{Hz}
\]
### Final Answer:
The apparent frequency observed by the observer when the source is moving away from them is \( 750 \, \text{Hz} \).
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