The increasing order of nucleophilicity of the following nucleophiles is :
(a). `CH_(3)CO_(2)^(ɵ)`
(b). `H_(2)O`
(c). `CH_(3)SO_(3)^(ɵ)`
(d). `overset(ɵ)(O)H`

Options

A. `altdltcltb`
B. `bltcltdlta`
C. `dltaltcltb`
D. `bltcltaltd`

Answer

To determine the increasing order of nucleophilicity among the given nucleophiles:

1. **Identify the Nucleophiles**:
- (a) `CH₃CO₂⁻` (acetate ion)
- (b) `H₂O` (water)
- (c) `CH₃SO₃⁻` (methanesulfonate ion)
- (d) `OH⁻` (hydroxide ion)

2. **Understand Nucleophilicity**:
- Nucleophilicity refers to the ability of a species to donate an electron pair to an electrophile.
- Generally, negatively charged nucleophiles are more nucleophilic than neutral ones.

3. **Classify the Nucleophiles**:
- `H₂O` is neutral.
- `CH₃CO₂⁻`, `CH₃SO₃⁻`, and `OH⁻` are negatively charged.

4. **Assess the Neutral Nucleophile**:
- Since `H₂O` is neutral, it will have the lowest nucleophilicity compared to the negatively charged nucleophiles.

5. **Compare the Negatively Charged Nucleophiles**:
- **Resonance Stabilization**:
- `CH₃CO₂⁻` (acetate ion) has resonance structures that delocalize the negative charge, making it more stable and less nucleophilic.
- `CH₃SO₃⁻` (methanesulfonate ion) has more resonance structures (three) compared to acetate (two), making it even more stable and less nucleophilic.
- `OH⁻` (hydroxide ion) does not have resonance stabilization, making it a stronger nucleophile.

6. **Rank the Nucleophiles**:
- Based on the above analysis:
- `H₂O` (neutral) < `CH₃CO₂⁻` (acetate ion, resonance stabilization) < `CH₃SO₃⁻` (methanesulfonate ion, more resonance stabilization) < `OH⁻` (hydroxide ion, no resonance stabilization).

7. **Final Order**:
- The increasing order of nucleophilicity is:
- `H₂O` < `CH₃CO₂⁻` < `CH₃SO₃⁻` < `OH⁻`

### Final Answer:
The increasing order of nucleophilicity is:
`H₂O` < `CH₃CO₂⁻` < `CH₃SO₃⁻` < `OH⁻`