The minimum amount of `O_(2)` (g) consumed per gram of reactant is for the reaction: (Given atomic mass: Fe = 56, O = 16, Mg = 24, P = 31, C = 12, H = 1)
A
`4Fe(s)+3O_(2)(g)to2Fe_(2)O_(3)(s)`
B
`P_(4)(s)+5O_(2)(g)toP_(4)O_(10)(s)`
C
`C_(3)H_(8)(g)+5O_(2)(g)to3CO_(2)(g)+4H_(2)O(I)`
D
`2Mgj(sJ)+O_(2)(g)to2MgO_(s)`
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The correct Answer is:
A
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