Home
Class 12
CHEMISTRY
1g of a non-volatile non-electrolyte sol...

1g of a non-volatile non-electrolyte solute is dissolved in 100g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1 : 5. The ratio of the elevation in their boiling points, `(DeltaT_(b)(A))/(DeltaT_(b)(B))` is

A

`5:1`

B

`10:1`

C

`1:5`

D

`1:02`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • JEE MAINS

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise QUESTION|1 Videos
  • JEE MAIN

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise CHEMISTRY|146 Videos
  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise CHEMSITRY|23 Videos

Similar Questions

Explore conceptually related problems

1g of same non volatile solute is added to 100g of two different solvents A and B . K_(b) of A:B=1:5 Find out ((DeltaT_(b))_(A))/((DeltaT_(b))_(B))

A' gram of non-volatile, non-electrolyte (molar mass M) is dissolved in 200 ml of unknown solvent (density =1.25 gm//ml molal elevation constant is K_(b) ) .Elevation in boiling point of this solution can be given by

When 10 of a non-volatile solute is dissolved in 100 g of benzene . It raises boiling point by 1^(@)C then moles mass of the solute is ______.

What mass of non-volatile solute, sucrose, need to be dissolved in 100g of water to decrease the vapour pressure of water by 30%?

5g each of two solutes X and Y ( mol. wt of X gt Y) are dissolved in 100g each of same solvent.

If 8g of a non-electrolyte solute is dissolved in 114g of n-octane to educe its vapour pressure to 80% , the molar mass of the solute is [ given molar mass of n-octane is 114g mol^(-1) ]

For a dilute solution containing 2.5 g of a non-volatile non-electrolyte solution in 100g of water, the elevation in boiling point at 1 atm pressure is 2^(@)C . Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of Hg) of the solution is: (take k_(b) = 0.76 K kg mol^(-1))

If 1 g of solute (molar mass = 50 g mol^(-1) ) is dissolved in 50 g of solvent and the elevation in boiling point is 1 K. The molar boiling constant of the solvent is

Solution A is obtained by dissolving 1 g of urea in 100 g of water and solution B is obtained by dissolving 1 g of glucose in 100 g of water. Which solution will have a higher boiling point and why?

Two solutions of non-volatile and non-electrolyte solute A and B are prepared separately. The molar mass ratio (M_(A))/(M_(B))=1/3 . Both are prepared as 5% by weight solution in water. Then what is the ratio of freezing point depresions, ((DeltaT_(f))_(A))/((DeltaT_(f))_(B)) of the solutions?