The truth table for the circuit given in the fig. is
A
`|{:(A,B,Y),(0,0,1),(0,1,1),(1,0,1),(1,1,1):}|`
B
`|{:(A,B,Y),(0,0,1),(0,1,0),(1,0,0),(1,1,0):}|`
C
`|{:(A,B,Y),(0,0,1),(0,1,1),(1,0,0),(1,1,0):}|`
D
`|{:(A,B,Y),(0,0,0),(0,1,0),(1,0,1),(1,1,1):}|`
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The correct Answer is:
C
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