Given : `Co^(3+)+e^(-)rarr Co^(2+), E^(@)=+1.181V` `Pb^(4+)+2e^(-)rarrPb^(2+),E^(@)=+1.67V` `Ce^(4+)+e^(-) rarr Ce^(3+), E^(@)=+1.61V` `Bi^(3+)+3e^(-)rarr Bi, E^(@)=+0.20V` Oxidizing power of the species will increase in the order:
A
`Ce^(4+)ltPb^(4+)ltBi^(3+)ltCo^(3+)`
B
`Bi^(3+)ltCe^(4+)ltPb^(4+)ltCo^(3+)`
C
`Co^(3+)ltCe^(4+)ltBi^(3+)ltPb^(4+)`
D
`Co^(3+)ltPb^(4+)ltCe^(4+)ltBi^(3+)`
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The correct Answer is:
B
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