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A tuning fork of frequency 480 Hz is use...

A tuning fork of frequency `480 Hz` is used in an experiment for measuring speed of sound (v) in air by resonance tube method. Resonance is observed to occur at two successive lengths of the air column, `l_(1) = 30 cm` and `l_(2) = 70 cm`. Then, `v` is equal to :

A

`332 ms^(-1)`

B

`384 ms^(-1)`

C

`338 ms^(-1)`

D

`379 ms^(-1)`

Text Solution

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The correct Answer is:
To find the speed of sound in air using the resonance tube method, we can follow these steps: ### Step 1: Understand the resonance condition In a closed organ pipe (like the resonance tube), the resonance occurs at odd multiples of \(\frac{\lambda}{4}\). The lengths of the air column at which resonance occurs can be expressed as: \[ L_n = \frac{(2n - 1) \lambda}{4} \] where \(L_n\) is the length of the air column for the \(n^{th}\) resonance. ### Step 2: Set up the equations for the two lengths Given the two successive lengths of the air column where resonance occurs: - \(L_1 = 30 \, \text{cm}\) - \(L_2 = 70 \, \text{cm}\) We can write the equations for these lengths: 1. For \(L_1\) (when \(n = n\)): \[ L_1 = \frac{(2n - 1) \lambda}{4} = 30 \, \text{cm} \] 2. For \(L_2\) (when \(n = n + 1\)): \[ L_2 = \frac{(2(n + 1) - 1) \lambda}{4} = 70 \, \text{cm} \] ### Step 3: Simplify the equations From the first equation: \[ (2n - 1) \lambda = 120 \, \text{cm} \quad \text{(1)} \] From the second equation: \[ (2n + 1) \lambda = 280 \, \text{cm} \quad \text{(2)} \] ### Step 4: Subtract the two equations Now, we subtract equation (1) from equation (2): \[ (2n + 1) \lambda - (2n - 1) \lambda = 280 \, \text{cm} - 120 \, \text{cm} \] This simplifies to: \[ 2\lambda = 160 \, \text{cm} \] Thus, we find: \[ \lambda = 80 \, \text{cm} \] ### Step 5: Calculate the speed of sound The speed of sound \(v\) can be calculated using the formula: \[ v = f \cdot \lambda \] where \(f\) is the frequency of the tuning fork. Given \(f = 480 \, \text{Hz}\) and \(\lambda = 80 \, \text{cm} = 0.8 \, \text{m}\): \[ v = 480 \, \text{Hz} \times 0.8 \, \text{m} = 384 \, \text{m/s} \] ### Final Answer The speed of sound \(v\) in air is: \[ \boxed{384 \, \text{m/s}} \] ---
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