Home
Class 12
PHYSICS
In an experiment ,electrons are accelera...

In an experiment ,electrons are accelerated from rest, by applying a voltage of 500 V.Calculate the radius of the path if a magnetic field 100 m T is then applied .Charge of the electron `=1.6 xx 10^-19 C `
Mass of the electron `=9.1 xx 10 ^(-31)` Kgl

A

`7.5 xx 10^3 m`

B

`7.5 xx 10 ^2 m`

C

7.5 m

D

`7.5 xx 10 ^-4 m`

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • JEE MAINS

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise Chemistry|1 Videos
  • JEE MAIN

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise All Questions|452 Videos
  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise PHYSICS|250 Videos

Similar Questions

Explore conceptually related problems

The mass of half mole of electrons is about (Given: Mass of electron =9.1 xx10^(-28) g)

An X-ray tube operates at 20k V . Find the maximum speed of the electron strinking the anode , given the charge of electron is 1.6 xx 10^(-19) coulomb and mass of electron is 9 xx 10^(-31) kg .

Molar mass of electron is nearly : (N_(A) = 6 xx 10^(23)) , mass of e^(-) = 9.1 xx 10^(-31)Kg

Calculate the uncertainty in the position (Delta x) of an electron if Delta v is 0.1 % .Take the velocity of electron = 2.2 xx10^(6) ms^(-1) and mass of electron as 9.108 xx 10^(-31)kg

Calculate the product of the uncertainty of the displacement and velocity of a electron having mass 9.1 xx 10^(-28) g

Suppose the an electron in the picture tube of a televisoin set is accelerated from rest through a potential differnece V_(b)-V_(a)= V_(ba) = +5000V . (a) What is the change in electric potential energy of the electron? (b) What is the speed of the electron ( m = 9.1 xx 10^(-31) kg) as a result of this acceleration ?

An electron moving along the x-axis with an initial energy of 100 eV enters a region of magnetic field vec(B) = (1.5 xx 10^(-3) T) hat (k) at S (see figure). The field extends between x=0 and x=2 cm . The electron is detected at the point Q on a screen placed 8 cm away from the point S . The distance d between P and Q (on the screen) is : (electron's charge = 1.6 xx 10^(-19) C , mass of electron = 9.1 xx 10^(-31) kg ). a) 11.65cm. b) 12.87 cm c) 1.22cm d) 2.25cm

An electron accelerated through 500 V , enters a transverse uniform magnetic field of magnitude 100 mT . The radius of the circular path described by the electron is nearly

The kinetic energy of an electron is 4.55 xx 10^(-25) J .The mass of electron is 9.1 xx 10^(-34) kg . Calculate velocity of the electron.

An electron of energy 1800 eV describes a circular path in magnetic field of flux density 0.4 T. The radius of path is (q = 1.6 xx 10^(-19) C, m_(e)=9.1 xx 10^(-31) kg)