A motor cycle starts from rest and accelerates along a straight path at `2m//s^(2)`. At the starting point of the motor cycle there is a stationary electric siren. How far has the motor cycle gone when the driver hears the frequency of the siren at `94%` of its value when the motor cycle was at rest ? (Speed of sound = `330ms^(-2))`
A motor cycle starts from rest and accelerates along a straight path at `2m//s^(2)`. At the starting point of the motor cycle there is a stationary electric siren. How far has the motor cycle gone when the driver hears the frequency of the siren at `94%` of its value when the motor cycle was at rest ? (Speed of sound = `330ms^(-2))`
A
49 m
B
98 m
C
147 m
D
196 m
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem, we will follow these steps:
### Step 1: Understand the problem
The motorcycle accelerates from rest at a rate of \(2 \, \text{m/s}^2\). We need to find the distance traveled by the motorcycle when the driver hears the frequency of the siren at \(94\%\) of its original value.
### Step 2: Set up the frequency equation
The apparent frequency \(f'\) heard by the observer (motorcycle driver) moving away from the stationary source (siren) can be expressed using the Doppler effect formula:
\[
f' = f_0 \left( \frac{v - v_o}{v} \right)
\]
where:
- \(f_0\) is the original frequency of the siren,
- \(v\) is the speed of sound (\(330 \, \text{m/s}\)),
- \(v_o\) is the speed of the observer (motorcycle).
### Step 3: Set the equation for \(94\%\) of the original frequency
We want the apparent frequency to be \(94\%\) of the original frequency:
\[
f' = 0.94 f_0
\]
Substituting this into the frequency equation gives:
\[
0.94 f_0 = f_0 \left( \frac{v - v_o}{v} \right)
\]
### Step 4: Simplify the equation
Dividing both sides by \(f_0\) (assuming \(f_0 \neq 0\)):
\[
0.94 = \frac{v - v_o}{v}
\]
Rearranging gives:
\[
0.94v = v - v_o
\]
\[
v_o = v - 0.94v = 0.06v
\]
### Step 5: Calculate the speed of the observer
Substituting \(v = 330 \, \text{m/s}\):
\[
v_o = 0.06 \times 330 = 19.8 \, \text{m/s}
\]
### Step 6: Use kinematics to find the distance traveled
Using the third equation of motion:
\[
v_o = u + at
\]
where \(u = 0\) (initial velocity), \(a = 2 \, \text{m/s}^2\), and \(t\) is the time taken. We can rearrange this to find \(t\):
\[
t = \frac{v_o}{a} = \frac{19.8}{2} = 9.9 \, \text{s}
\]
### Step 7: Calculate the distance traveled
Using the formula for distance:
\[
s = ut + \frac{1}{2} a t^2
\]
Substituting \(u = 0\):
\[
s = \frac{1}{2} \cdot 2 \cdot (9.9)^2
\]
\[
s = 1 \cdot 98.01 = 98.01 \, \text{m}
\]
### Final Result
The motorcycle has traveled approximately \(98 \, \text{m}\) when the driver hears the frequency of the siren at \(94\%\) of its original value.
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