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A radar has a power of 1kW and is operat...

A radar has a power of `1kW` and is operating at a frequency of `10 GHz`. It is located on a mountain top of height `500m`. The maximum distance upto which it can detect object located on the surface of the earth (Radius of earth `6.4xx10^(6)m`) is

A

80 km

B

16 km

C

40 km

D

64 km

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the maximum distance up to which a radar can detect an object located on the surface of the Earth, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Values**: - Power of the radar: \( P = 1 \, \text{kW} \) (not directly needed for this calculation) - Frequency of the radar: \( f = 10 \, \text{GHz} \) (not directly needed for this calculation) - Height of the mountain: \( h = 500 \, \text{m} = 0.5 \, \text{km} \) - Radius of the Earth: \( R = 6.4 \times 10^6 \, \text{m} = 6400 \, \text{km} \) 2. **Set Up the Geometry**: - The radar is located at a height \( h \) above the Earth's surface. The distance \( d \) we want to find is the horizontal distance from the base of the mountain to the point where the radar can detect an object on the surface of the Earth. - The situation can be visualized as a right triangle where: - One leg is the radius of the Earth \( R \). - The other leg is the height \( h \). - The hypotenuse is \( R + h \). 3. **Apply Pythagorean Theorem**: - According to the Pythagorean theorem: \[ (R + h)^2 = R^2 + d^2 \] - Expanding the left side: \[ R^2 + 2Rh + h^2 = R^2 + d^2 \] 4. **Simplify the Equation**: - Cancel \( R^2 \) from both sides: \[ 2Rh + h^2 = d^2 \] - Since \( h \) is much smaller than \( R \), we can ignore \( h^2 \): \[ d^2 \approx 2Rh \] 5. **Calculate the Distance \( d \)**: - Substitute the values of \( R \) and \( h \): \[ d = \sqrt{2Rh} \] - Convert \( R \) to kilometers: \[ R = 6400 \, \text{km} = 6.4 \times 10^6 \, \text{m} \] - Substitute \( R = 6400 \, \text{km} \) and \( h = 0.5 \, \text{km} \): \[ d = \sqrt{2 \times 6400 \times 0.5} \] \[ d = \sqrt{6400} = 80 \, \text{km} \] 6. **Final Result**: - The maximum distance up to which the radar can detect an object located on the surface of the Earth is \( d = 80 \, \text{km} \).
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