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Assume that a neutron breaks into a prot...

Assume that a neutron breaks into a proton and an electron . The energy reased during this process is (mass of neutron `= 1.6725 xx 10^(-27) kg` mass of proton `= 1.6725 xx 10^(-27) kg` mass of electron `= 9 xx 10^(-31) kg )`

A

0.73 MeV

B

7.10 MeV

C

6.30 MeV

D

5.4 MeV

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To find the energy released during the process of a neutron breaking into a proton and an electron, we can follow these steps: ### Step 1: Identify the masses involved - Mass of neutron (m_n) = \(1.6725 \times 10^{-27} \, \text{kg}\) - Mass of proton (m_p) = \(1.6725 \times 10^{-27} \, \text{kg}\) - Mass of electron (m_e) = \(9 \times 10^{-31} \, \text{kg}\) ### Step 2: Calculate the change in mass (Δm) The change in mass when a neutron breaks into a proton and an electron can be calculated using the formula: \[ \Delta m = m_p + m_e - m_n \] Substituting the values: \[ \Delta m = (1.6725 \times 10^{-27} \, \text{kg}) + (9 \times 10^{-31} \, \text{kg}) - (1.6725 \times 10^{-27} \, \text{kg}) \] \[ \Delta m = 9 \times 10^{-31} \, \text{kg} \] ### Step 3: Calculate the energy released (E) Using Einstein's mass-energy equivalence principle, the energy released can be calculated using the formula: \[ E = \Delta m \cdot c^2 \] where \(c\) (the speed of light) is approximately \(3 \times 10^8 \, \text{m/s}\). Thus: \[ E = (9 \times 10^{-31} \, \text{kg}) \cdot (3 \times 10^8 \, \text{m/s})^2 \] Calculating \(c^2\): \[ c^2 = (3 \times 10^8)^2 = 9 \times 10^{16} \, \text{m}^2/\text{s}^2 \] Now substituting back into the energy equation: \[ E = (9 \times 10^{-31} \, \text{kg}) \cdot (9 \times 10^{16} \, \text{m}^2/\text{s}^2) \] \[ E = 8.1 \times 10^{-14} \, \text{J} \] ### Step 4: Convert energy from Joules to electron volts (eV) To convert Joules to electron volts, we use the conversion factor \(1 \, \text{eV} = 1.6 \times 10^{-19} \, \text{J}\): \[ E = \frac{8.1 \times 10^{-14} \, \text{J}}{1.6 \times 10^{-19} \, \text{J/eV}} \approx 5.06 \times 10^5 \, \text{eV} \] Converting to mega electron volts (MeV): \[ E \approx 0.506 \, \text{MeV} \] ### Final Answer The energy released during the process of a neutron breaking into a proton and an electron is approximately **0.506 MeV**.
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