Assume that a neutron breaks into a proton and an electron . The energy reased during this process is (mass of neutron `= 1.6725 xx 10^(-27) kg` mass of proton `= 1.6725 xx 10^(-27) kg` mass of electron `= 9 xx 10^(-31) kg )`
Assume that a neutron breaks into a proton and an electron . The energy reased during this process is (mass of neutron `= 1.6725 xx 10^(-27) kg` mass of proton `= 1.6725 xx 10^(-27) kg` mass of electron `= 9 xx 10^(-31) kg )`
A
0.73 MeV
B
7.10 MeV
C
6.30 MeV
D
5.4 MeV
Text Solution
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The correct Answer is:
To find the energy released during the process of a neutron breaking into a proton and an electron, we can follow these steps:
### Step 1: Identify the masses involved
- Mass of neutron (m_n) = \(1.6725 \times 10^{-27} \, \text{kg}\)
- Mass of proton (m_p) = \(1.6725 \times 10^{-27} \, \text{kg}\)
- Mass of electron (m_e) = \(9 \times 10^{-31} \, \text{kg}\)
### Step 2: Calculate the change in mass (Δm)
The change in mass when a neutron breaks into a proton and an electron can be calculated using the formula:
\[
\Delta m = m_p + m_e - m_n
\]
Substituting the values:
\[
\Delta m = (1.6725 \times 10^{-27} \, \text{kg}) + (9 \times 10^{-31} \, \text{kg}) - (1.6725 \times 10^{-27} \, \text{kg})
\]
\[
\Delta m = 9 \times 10^{-31} \, \text{kg}
\]
### Step 3: Calculate the energy released (E)
Using Einstein's mass-energy equivalence principle, the energy released can be calculated using the formula:
\[
E = \Delta m \cdot c^2
\]
where \(c\) (the speed of light) is approximately \(3 \times 10^8 \, \text{m/s}\). Thus:
\[
E = (9 \times 10^{-31} \, \text{kg}) \cdot (3 \times 10^8 \, \text{m/s})^2
\]
Calculating \(c^2\):
\[
c^2 = (3 \times 10^8)^2 = 9 \times 10^{16} \, \text{m}^2/\text{s}^2
\]
Now substituting back into the energy equation:
\[
E = (9 \times 10^{-31} \, \text{kg}) \cdot (9 \times 10^{16} \, \text{m}^2/\text{s}^2)
\]
\[
E = 8.1 \times 10^{-14} \, \text{J}
\]
### Step 4: Convert energy from Joules to electron volts (eV)
To convert Joules to electron volts, we use the conversion factor \(1 \, \text{eV} = 1.6 \times 10^{-19} \, \text{J}\):
\[
E = \frac{8.1 \times 10^{-14} \, \text{J}}{1.6 \times 10^{-19} \, \text{J/eV}} \approx 5.06 \times 10^5 \, \text{eV}
\]
Converting to mega electron volts (MeV):
\[
E \approx 0.506 \, \text{MeV}
\]
### Final Answer
The energy released during the process of a neutron breaking into a proton and an electron is approximately **0.506 MeV**.
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