The electrons, identified by quantum numbers n and l (i) `n=4l=1` (ii) `n=4l=0` (iii) `n=3l=2` (iv) `n=3l=1` can be placed in increasing order of energy from the lowest to highest as
A
n = 4, I = 1
B
n = 4, I = 0
C
n = 3, I = 2
D
n = 3, I = 1
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The correct Answer is:
B
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