Home
Class 12
PHYSICS
An ideal gas under goes a quasi static, ...

An ideal gas under goes a quasi static, reversible process in which its molar heat capacity C remains constant. If during this process the relation of pressure P and volume V is given by `PV^n=constant`, then n is given by (Here `C_P and C_V` are molar specific heat at constant pressure and constant volume, respectively):

A

`n=(C-C_(p))/(C-C_(v))`

B

`n=(C_(p)-C)/(C-C_(v))`

C

`n=(C-C_(v))/(C-C_(p))`

D

`n=(C_(p))/(C_(v))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( n \) in terms of the molar heat capacities \( C_P \) and \( C_V \) given that the gas follows the relation \( PV^n = \text{constant} \) during a quasi-static, reversible process where the molar heat capacity \( C \) remains constant. ### Step-by-Step Solution: 1. **Understand the Relationship**: The process described is a polytropic process, where the relationship between pressure \( P \) and volume \( V \) is given by \( PV^n = \text{constant} \). 2. **Molar Heat Capacity Relation**: For a polytropic process, the molar heat capacity \( C \) can be expressed as: \[ C = C_V + \frac{R}{1 - n} \] where \( R \) is the universal gas constant. 3. **Rearranging the Equation**: We can rearrange the above equation to isolate \( n \): \[ C - C_V = \frac{R}{1 - n} \] 4. **Cross-Multiplying**: Cross-multiplying gives: \[ (C - C_V)(1 - n) = R \] 5. **Expanding the Equation**: Expanding the left-hand side: \[ C - C_V - n(C - C_V) = R \] 6. **Isolating \( n \)**: Rearranging this equation to isolate \( n \): \[ n(C - C_V) = C - C_V - R \] \[ n = \frac{C - C_V - R}{C - C_V} \] 7. **Substituting \( R \)**: We know that \( R = C_P - C_V \). Substituting this into the equation gives: \[ n = \frac{C - C_V - (C_P - C_V)}{C - C_V} \] Simplifying this: \[ n = \frac{C - C_P}{C - C_V} \] 8. **Final Result**: Thus, the final expression for \( n \) is: \[ n = \frac{C - C_P}{C - C_V} \] ### Conclusion: The value of \( n \) in terms of the molar heat capacities \( C_P \) and \( C_V \) is given by: \[ n = \frac{C - C_P}{C - C_V} \]
Promotional Banner

Topper's Solved these Questions

  • JEE MAINS

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise Chemistry|1 Videos
  • JEE MAIN

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise All Questions|452 Videos
  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise PHYSICS|250 Videos

Similar Questions

Explore conceptually related problems

When water is heated from 0^(@)C to 4^(@)C and C_(P) and C_(V) are its specific heats at constant pressure and constant volume respectively , then :-

If C_P and C_V denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then

For an ideal gas, the heat of reaction at constant pressure and constant volume are related as

The molar heat capacity for a gas at constant T and P is

C_v and C_p denote the molar specific heat capacities of a gas at constant volume and constant pressure, respectively. Then

C_v and C_p denote the molar specific heat capacities of a gas at constant volume and constant pressure, respectively. Then

C_v and C_p denote the molar specific heat capacities of a gas at constant volume and constant pressure, respectively. Then

C_v and C_p denote the molar specific heat capacities of a gas at constant volume and constant pressure, respectively. Then

If C_(p) and C_(v) denoted the specific heats of unit mass of nitrogen at constant pressure and volume respectively, then

If C_(p) and C_(v) denoted the specific heats of unit mass of nitrogen at constant pressure and volume respectively, then