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For a common emiter configuration if a a...

For a common emiter configuration if `a` and `beta` have their usualy meaning , the incorrrect relationship between `a and beta` is :

A

`alpha = (beta)/(1-beta)`

B

`alpha = (beta)/(1+beta)`

C

`alpha = (beta^(2))/(1+beta^(2))`

D

`(1)/(alpha)=(1)/(beta)+1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the relationships between alpha (α) and beta (β) in a common emitter configuration, let's go through the steps systematically. ### Step-by-Step Solution: 1. **Understanding Definitions**: - In a common emitter configuration, the current gain is defined as: - **Alpha (α)**: The ratio of collector current (Ic) to emitter current (Ie). \[ \alpha = \frac{I_c}{I_e} \] - **Beta (β)**: The ratio of collector current (Ic) to base current (Ib). \[ \beta = \frac{I_c}{I_b} \] 2. **Relation between Ic, Ib, and Ie**: - The emitter current (Ie) is the sum of the collector current (Ic) and the base current (Ib): \[ I_e = I_c + I_b \] 3. **Expressing Ib in terms of Ic and β**: - From the definition of β: \[ I_b = \frac{I_c}{\beta} \] - Substituting this into the equation for Ie: \[ I_e = I_c + \frac{I_c}{\beta} = I_c \left(1 + \frac{1}{\beta}\right) \] 4. **Expressing Ic in terms of α and Ie**: - From the definition of α: \[ I_c = \alpha I_e \] 5. **Combining the equations**: - Substitute \(I_c\) from the α equation into the equation for Ie: \[ I_e = \alpha I_e + \frac{\alpha I_e}{\beta} \] - Factor out \(I_e\) (assuming \(I_e \neq 0\)): \[ 1 = \alpha + \frac{\alpha}{\beta} \] 6. **Rearranging the equation**: - Rearranging gives: \[ 1 = \alpha \left(1 + \frac{1}{\beta}\right) \] - This leads to: \[ \frac{1}{\alpha} = 1 + \frac{1}{\beta} \] 7. **Finding the relationship between α and β**: - Rearranging the above equation gives: \[ \frac{1}{\alpha} - 1 = \frac{1}{\beta} \] - This can be simplified to: \[ \beta = \frac{\alpha}{1 - \alpha} \] 8. **Final relationships**: - We have two important relationships: - \( \alpha = \frac{\beta}{1 + \beta} \) - \( \beta = \frac{\alpha}{1 - \alpha} \) 9. **Identifying the incorrect relationship**: - Now, we need to check which of the given relationships is incorrect. The relationships we derived are: - \( \alpha = \frac{\beta}{1 + \beta} \) (Correct) - \( \beta = \frac{\alpha}{1 - \alpha} \) (Correct) - Any other relationships provided in the question that do not match these derived relationships can be considered incorrect. ### Conclusion: The incorrect relationships between α and β in the given options are those that do not match the derived equations.
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