Home
Class 12
PHYSICS
A particle of mass m is acted upon by a ...

A particle of mass m is acted upon by a force F given by the emprical law `F=(R)/(t^2)upsilon(t)`
If this law is to be tested experimentally by observing the motion starting from rest, the best way is to plot :

A

`upsilon(t) "against "t^2`

B

log `upsilon(t)" anainst "(1)/(t^2)`

C

log `upsilon (t)` against t

D

`log upsilon (t)" against "(1)/(t)`

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • JEE MAINS

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise Chemistry|1 Videos

  • JEE MAIN

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise All Questions|452 Videos

  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise PHYSICS|250 Videos

Similar Questions

Explore conceptually related problems

A particle of mass m is acted upon by a force F= t^2-kx . Initially , the particle is at rest at the origin. Then

A block of mass m at rest is acted upon by a force F for a time t. The kinetic energy of block after time t is

The velocity vecv of a particle of mass 'm' acted upon by a constant force is given by vecv (t) = A[cos (kt) bari - sin (kt) barj] . Then the angle between the force and the momentum of the particle is (Here A and k are constants)

A particle is acted upon by a force given by F=(12t-3t^(2)) N, where is in seconds. Find the change in momenum of that particle from t=1 to t=3 sec.

Passage XII)_ A particle of mass m is constrained to move along x-axis. A force F acts on the particle. F always points toward the position labelled E. For example, when the particle is to the left of E,Fpoints to the right. The magnitude of F is consant except at point E where it is zero. The systm is horizontal. F is the net force acting on the particle. the particle is displaced a distance A towards left from the equilibrium position E and released from rest at t=0. What it is the time period of periodic motion of particle.

Passage XII)_ A particle of mass m is constrained to move along x-axis. A force F acts on the particle. F always points toward the position labelled E. For example, when the particle is to the left of E,Fpoints to the right. The magnitude of F is consant except at point E where it is zero. The systm is horizontal. F is the net force acting on the particle. the particle is displaced a distance A towards left from the equilibrium position E and released from rest at t=0. Velocity-time graph of the particle is

A particle of mass m initially at rest is acted upon by a unidirectional force F=F_@cos ((pi)/(2) t) . The distance travelled by the particle when it stops first in the subsequent motion is ,

A particle of mass m initially at rest. A variabl force acts on the particle f=kx^(2) where k is a constant and x is the displacment. Find the work done by the force f when the speed of particles is v.

A particle of mass m is driven by a machine that delivers a constant power k watts. If the particle starts from rest the force on the particle at time t is

A particle of mass 70 g, moving at 50 cm/s , is acted upon by a variable force opposite to its direction of motion. The force F is shown as a function of time t (a) its speed will be 50 cm/s after the force stops acting (b) its direction of motion will reverse (c) its average acceleration will be 1 m//s^2 during the interval in which the force acts its average acceleration will be 10 m//s^2 during the interval in which the force acts