A compressive force, F is applied at the two ends of a long thin steel rod. It is heated, simultaneously, such that its temeprature increass by `DeltaT`. The net change in its length is zero. Let l be the length of the rod, A its area of cross-section, Y its Young's modulus, and `alpha` its coefficient of linear expansion. Then, F is equal to
A compressive force, F is applied at the two ends of a long thin steel rod. It is heated, simultaneously, such that its temeprature increass by `DeltaT`. The net change in its length is zero. Let l be the length of the rod, A its area of cross-section, Y its Young's modulus, and `alpha` its coefficient of linear expansion. Then, F is equal to
A
`IA Y alpha Delta T`
B
`A Y alpha Delta T`
C
`(AY)/(alpha DeltaT)`
D
`I^(2) Yalpha Delta T`
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem, we need to analyze the effects of both the compressive force and the temperature change on the length of the steel rod.
### Step-by-Step Solution:
1. **Understand the Effects of Temperature Change**:
- When the rod is heated, it tends to expand. The change in length (\( \Delta L \)) due to the temperature increase (\( \Delta T \)) can be expressed using the formula:
\[
\Delta L_{\text{thermal}} = \alpha L \Delta T
\]
- Here, \( \alpha \) is the coefficient of linear expansion, \( L \) is the original length of the rod, and \( \Delta T \) is the change in temperature.
2. **Understand the Effects of Compressive Force**:
- The compressive force \( F \) causes a change in length in the opposite direction. The relationship between the force, area of cross-section \( A \), Young's modulus \( Y \), and change in length due to the force can be expressed as:
\[
\Delta L_{\text{compression}} = -\frac{F}{A} \cdot \frac{L}{Y}
\]
- Here, the negative sign indicates that this change in length is a contraction.
3. **Set Up the Equation for Net Change in Length**:
- Since the net change in length is zero, we can set the two changes in length equal to each other:
\[
\Delta L_{\text{thermal}} + \Delta L_{\text{compression}} = 0
\]
- Substituting the expressions we derived:
\[
\alpha L \Delta T - \frac{F}{A} \cdot \frac{L}{Y} = 0
\]
4. **Solve for the Compressive Force \( F \)**:
- Rearranging the equation gives:
\[
\alpha L \Delta T = \frac{F}{A} \cdot \frac{L}{Y}
\]
- Cancel \( L \) from both sides (assuming \( L \neq 0 \)):
\[
\alpha \Delta T = \frac{F}{A Y}
\]
- Now, solving for \( F \):
\[
F = A Y \alpha \Delta T
\]
5. **Final Result**:
- Therefore, the expression for the compressive force \( F \) is:
\[
F = A Y \alpha \Delta T
\]
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