A metal ‘M’ reacts with nitrogen gas to afford `'M_(3)N' . 'M_(3)N'` on heating at high temperature gives back ‘M’ and on reaction with water produces a gas ‘B’. Gas ‘B’ reacts with aqueous solution of `CuSO_(4)` to form a deep blue compound. ‘M’ and ‘B’ respectively are :
A metal ‘M’ reacts with nitrogen gas to afford `'M_(3)N' . 'M_(3)N'` on heating at high temperature gives back ‘M’ and on reaction with water produces a gas ‘B’. Gas ‘B’ reacts with aqueous solution of `CuSO_(4)` to form a deep blue compound. ‘M’ and ‘B’ respectively are :
A
`"Li and NH"_(3)`
B
`"Na and NH"_(3)`
C
`"Ba and N"_(2)`
D
`"Al and N"_(2)`
Text Solution
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To solve the problem step by step, let's analyze the information given in the question:
1. **Identify the Reaction of Metal M with Nitrogen**:
The metal 'M' reacts with nitrogen gas to form a compound denoted as M₃N. This indicates that 'M' is likely a monovalent metal, as the formula suggests a 3:1 ratio of metal to nitrogen.
**Hint**: Consider the valency of the metal based on the formula M₃N.
2. **Heating M₃N**:
When M₃N is heated at high temperatures, it decomposes back into the metal 'M' and nitrogen gas (N₂). This reaction suggests that the metal nitride is relatively stable and can revert to its components upon heating.
**Hint**: Think about which metal nitrides are known to decompose upon heating.
3. **Reaction with Water**:
The metal nitride M₃N reacts with water to produce a gas 'B'. This gas is likely to be ammonia (NH₃), as many metal nitrides react with water to form hydroxides and ammonia.
**Hint**: Recall the common reactions of metal nitrides with water.
4. **Gas B Reacting with CuSO₄**:
The gas 'B' (which we suspect is ammonia) reacts with an aqueous solution of copper sulfate (CuSO₄) to form a deep blue compound. This deep blue compound is known to be the tetraamminecopper(II) complex, [Cu(NH₃)₄]²⁺.
**Hint**: Identify the deep blue compound formed when ammonia reacts with copper sulfate.
5. **Identifying Metal M**:
Now, we need to determine which metal could be 'M'. The options are likely to include metals like lithium (Li) and sodium (Na). Both can form nitrides (Li₃N and Na₃N). However, sodium nitride is known to be unstable at room temperature, while lithium nitride is stable.
**Hint**: Compare the stability of the nitrides formed by the metals in question.
6. **Final Conclusion**:
Based on the analysis, we conclude that:
- The metal 'M' is lithium (Li), as it forms lithium nitride (Li₃N) which is stable and can decompose to give lithium and nitrogen upon heating.
- The gas 'B' is ammonia (NH₃), which is produced when lithium nitride reacts with water and subsequently forms a deep blue complex with copper sulfate.
**Final Answer**: Metal M is lithium (Li) and gas B is ammonia (NH₃).
### Summary:
- **Metal M**: Lithium (Li)
- **Gas B**: Ammonia (NH₃)
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