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In an a.c. circuit, the instantaneous e....

In an a.c. circuit, the instantaneous e.m.f. and current are given by e = 100 sin 30 t
`i = 20 sin( 30t-(pi)/(4))` In one cycle of a.c., the average power consumed by the circuit and the wattless current are, respectively :

A

50,0

B

50,10

C

`(1000)/(sqrt(2)),10`

D

`(50)/(sqrt(2)),0`

Text Solution

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The correct Answer is:
To solve the given problem, we will follow these steps: ### Step 1: Identify the given parameters The instantaneous EMF and current are given as: - \( e(t) = 100 \sin(30t) \) - \( i(t) = 20 \sin(30t - \frac{\pi}{4}) \) From these equations, we can identify: - The peak voltage \( E_0 = 100 \) V - The peak current \( I_0 = 20 \) A ### Step 2: Calculate the phase difference \( \phi \) The phase difference \( \phi \) between the voltage and current can be determined from the current equation: - \( i(t) = 20 \sin(30t - \frac{\pi}{4}) \) Thus, the phase angle \( \phi = \frac{\pi}{4} \) radians. ### Step 3: Calculate the average power consumed in the circuit The formula for average power \( P \) in an AC circuit is given by: \[ P = \frac{E_0 I_0}{2} \cos(\phi) \] Substituting the values we have: - \( E_0 = 100 \) - \( I_0 = 20 \) - \( \phi = \frac{\pi}{4} \) (where \( \cos(\frac{\pi}{4}) = \frac{1}{\sqrt{2}} \)) Now substituting these values into the formula: \[ P = \frac{100 \times 20}{2} \cdot \cos\left(\frac{\pi}{4}\right) = \frac{2000}{2} \cdot \frac{1}{\sqrt{2}} = 1000 \cdot \frac{1}{\sqrt{2}} = \frac{1000}{\sqrt{2}} \text{ W} \] ### Step 4: Calculate the wattless current The wattless current \( I_w \) can be calculated using the formula: \[ I_w = I_{\text{rms}} \cdot \sin(\phi) \] Where \( I_{\text{rms}} = \frac{I_0}{\sqrt{2}} \). Calculating \( I_{\text{rms}} \): \[ I_{\text{rms}} = \frac{20}{\sqrt{2}} \text{ A} \] Now substituting into the wattless current formula: \[ I_w = \frac{20}{\sqrt{2}} \cdot \sin\left(\frac{\pi}{4}\right) = \frac{20}{\sqrt{2}} \cdot \frac{1}{\sqrt{2}} = \frac{20}{2} = 10 \text{ A} \] ### Final Answers - Average Power: \( \frac{1000}{\sqrt{2}} \) W - Wattless Current: \( 10 \) A
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