Home
Class 12
PHYSICS
At 27^@C two moles of an ideal monatomic...

At `27^@C` two moles of an ideal monatomic gas occupy a volume V. The gas expands adiabatically to a volume `2V`. Calculate
(a) final temperature of the gas
(b) change in its internal energy and
[ `R=8.31J//mol-K`]

A

`(a)195K" "(b)2.7kJ`

B

`(a)189K" "(b)2.7kJ`

C

`(a)195K" "(b)-2.7kJ`

D

`(a)189K" "(b)-2.7kJ`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will break it down into two parts: (a) calculating the final temperature of the gas after adiabatic expansion, and (b) calculating the change in internal energy. ### Given Data: - Initial temperature \( T_1 = 27^\circ C = 300 \, K \) - Initial volume \( V_1 = V \) - Final volume \( V_2 = 2V \) - Number of moles \( n = 2 \) - Universal gas constant \( R = 8.31 \, J/(mol \cdot K) \) - For a monatomic ideal gas, \( \gamma = \frac{5}{3} \approx 1.67 \) ### Part (a): Final Temperature of the Gas 1. **Use the adiabatic relation for temperature and volume:** \[ \frac{T_2}{T_1} = \left(\frac{V_1}{V_2}\right)^{\gamma - 1} \] 2. **Substituting the values:** \[ \frac{T_2}{300} = \left(\frac{V}{2V}\right)^{1.67 - 1} \] \[ \frac{T_2}{300} = \left(\frac{1}{2}\right)^{0.67} \] 3. **Calculating \( \left(\frac{1}{2}\right)^{0.67} \):** \[ \left(\frac{1}{2}\right)^{0.67} \approx 0.6156 \] 4. **Now, calculate \( T_2 \):** \[ T_2 = 300 \times 0.6156 \approx 184.68 \, K \approx 185 \, K \] ### Part (b): Change in Internal Energy 1. **Internal energy \( U \) of an ideal gas is given by:** \[ U = n C_v T \] Where \( C_v = \frac{R}{\gamma - 1} \). 2. **Calculate \( C_v \):** \[ C_v = \frac{8.31}{1.67 - 1} = \frac{8.31}{0.67} \approx 12.4 \, J/(mol \cdot K) \] 3. **Calculate initial internal energy \( U_1 \):** \[ U_1 = n C_v T_1 = 2 \times 12.4 \times 300 = 7440 \, J \] 4. **Calculate final internal energy \( U_2 \):** \[ U_2 = n C_v T_2 = 2 \times 12.4 \times 185 \approx 4584 \, J \] 5. **Change in internal energy \( \Delta U \):** \[ \Delta U = U_2 - U_1 = 4584 - 7440 = -2856 \, J \approx -2.86 \, kJ \] ### Final Answers: - (a) Final temperature \( T_2 \approx 185 \, K \) - (b) Change in internal energy \( \Delta U \approx -2.86 \, kJ \)
Promotional Banner

Topper's Solved these Questions

  • JEE MAINS

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise Chemistry|1 Videos
  • JEE MAIN

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise All Questions|452 Videos
  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise PHYSICS|250 Videos

Similar Questions

Explore conceptually related problems

At 27^@C two moles of an ideal monatomic gas occupy a volume V. The gas expands adiabatically to a volume 2V . Calculate (a) final temperature of the gas (b) change in its internal energy and (c) the work done by the gas during the process. [ R=8.31J//mol-K ]

Two moles of an ideal monatomic gas occupies a volume V at 27 °C. The gas expands adiabatically to a volume 2V. Calculate (i) the final temperature of the gas and (ii) change in its internal energy.

At 27^@C two moles of an ideal monoatomic gas occupy a volume V. The gas expands adiabatically to a volume 2V. Calculate (i) the final temperature of the gas, (ii) change in its internal energy, and (iii) the work done by the gas during this process.

At 27^(@)C two moles of an ideal monatomic gas occupy a volume. V The gas expands adiabatically to a volume 2V. Calculate (i) Final temperature of the gas (ii) change its internal energy and (iiI) Workd done by the gas during this process. Given R = 8.31 J//"mol" K, (2)^(2//3) = 1.587

Two moles of an ideal monoatomic gas occupy a volume 2V at temperature 300K, it expands to a volume 4V adiabatically, then the final temperature of gas is

An ideal monatomic gas at 300 K expands adiabatically to 8 times its volume . What is the final temperature ?

An ideal monoatomic gas at 300K expands adiabatically to twice its volume. What is the final temperature?

A monoatomic gas at a pressure p, having a volume 2V and then adiabatically to a volume 16 V. The final pressure of the gas is (take gamma = (5)/(3) )

One mole of an ideal monoatomic gas expands reversibly and adiabatically from a volume of x litre to 14 litre at 27^(@) C. Then value of x will be [Given, final temperature 189 K and C_(V) = 3/2 R].

A monatomic gas at a pressure P, having a volume V expands isothermally to a volume 2 V and then adiabatically to a volume 16 V. The final pressure of the gas is ( take gamma=5/3 )