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The dipole moment of a circular loop car...

The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is `B_(1)`. When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is `B_(2)`. The ratio `(B_(1))/(B_(2))` is:

A

`(1)/(sqrt(2))`

B

2

C

`sqrt(3)`

D

`sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
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