A capacitor `C_(1) =1.0 muF` is charged up to a voltage V=60 V by connecting it to battery B through switch (1) Now `C_(1)` is disconnected from battery and connected to a circuit consisting of two uncharged capaictors `C_(2)=3.0 mu F and C_(3)=6.0 mu F` through switch (2) as shown in the figure The sum of final charges on `C_(2) and c_(3)` is :
A
`40 mu C`
B
`36 mu C`
C
`20 mu C`
D
`54 mu C`
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