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Suppose an electron is attracted toward ...

Suppose an electron is attracted toward the origin by a force`(k)/(r )` where `k` is a constant and `r` is the distance of the electron from the origin .By applying Bohr model to this system the radius of the `n^(th)` orbital of the electron is found to be `r_(n)` and the kinetic energy of the electron to be `T_(n)` , Then which of the following is true ?

A

`T_(n) prop 1//n^(2), r_(n) prop n^(2)`

B

`T_(n) " independent of " n, r_(n) prop n`

C

`T_(n) prop 1/n, r_(n) prop n`

D

`T_(n) prop 1//n, r_(n) prop n^(2)`

Text Solution

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The correct Answer is:
To solve the problem, we will apply the principles of the Bohr model to determine the relationships between the radius of the nth orbital \( r_n \) and the kinetic energy \( T_n \) of the electron. ### Step-by-Step Solution: 1. **Understanding the Force**: The electron is attracted towards the origin by a force given by: \[ F = \frac{k}{r} \] where \( k \) is a constant and \( r \) is the distance from the origin. 2. **Centripetal Force**: For an electron moving in a circular orbit, the centripetal force required to keep the electron in that orbit is provided by the attractive force. Thus, we can write: \[ \frac{mv^2}{r} = \frac{k}{r} \] where \( m \) is the mass of the electron and \( v \) is its velocity. 3. **Solving for Velocity**: Rearranging the equation gives: \[ mv^2 = k \quad \Rightarrow \quad v^2 = \frac{k}{m} \] 4. **Kinetic Energy**: The kinetic energy \( T_n \) of the electron is given by: \[ T_n = \frac{1}{2} mv^2 \] Substituting \( v^2 \) from the previous step: \[ T_n = \frac{1}{2} m \left(\frac{k}{m}\right) = \frac{k}{2} \] This shows that \( T_n \) is a constant and does not depend on \( n \). 5. **Angular Momentum**: According to the Bohr model, the angular momentum \( L \) of the electron is quantized: \[ L = mvr = n\frac{h}{2\pi} \] where \( h \) is Planck's constant and \( n \) is the principal quantum number. 6. **Finding the Radius**: From the angular momentum equation, we can express \( r \): \[ r_n = \frac{n h}{2\pi mv} \] Substituting \( v \) from our earlier expression: \[ r_n = \frac{n h}{2\pi m \sqrt{\frac{k}{m}}} = \frac{n h}{2\pi} \cdot \frac{1}{\sqrt{k/m}} = \frac{n h \sqrt{m}}{2\pi \sqrt{k}} \] This shows that \( r_n \) is directly proportional to \( n \). ### Conclusion: From the analysis, we have: - The kinetic energy \( T_n \) is independent of \( n \) (constant). - The radius \( r_n \) is directly proportional to \( n \). Thus, the correct statement is: - \( T_n \) is independent of \( n \) and \( r_n \) is directly proportional to \( n \).
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