A thin semi-circular ring of radius r has a positive charge q distributed uniformly over it. The net field `vecE` at the centre O is
A
`(q)/(4pi^(2)epsilon_(0)r^(2))hatj`
B
`-(q)/(4pi^(2)epsilon_(0)r^(2))hatj`
C
`-(q)/(2pi^(2)epsilon_(0)r^(2))hatj`
D
`(q)/(2pi^(2)epsilon_(0)r^(2))hatj`
Text Solution
Verified by Experts
The correct Answer is:
C
Topper's Solved these Questions
JEE MAINS
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise Chemistry|1 Videos
JEE MAIN
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise All Questions|452 Videos
JEE MAINS 2020
JEE MAINS PREVIOUS YEAR ENGLISH|Exercise PHYSICS|250 Videos
Similar Questions
Explore conceptually related problems
A rubber balloon is given a charge Q distributed uniformly over its surface. Then
A ring of radius R has charge -Q distributed uniformly over it. Calculate the charge that should be placed at the center of the ring such that the electric field becomes zero at apoint on the axis of the ring at distant R from the center of the ring.
A thin fixed ring of radius a has a positive chage q unformly distributed over it.A particle of mass m having a megative charge Q, is placed on the axis at a distance of x(xltlta) form the center of the ring. Show that the motion of the negatively chaged particle is approximatly simple harmonic. Calculate the time period of oscillation.
A cjircular wire-loop of radius a carries a total charge Q distributed uniformly over its length . A small length dL of the wire is cut off. Find the electric field at the centre due to remaining wire.
A ring of radius a contains a charge q distributed. uniformly ober its length. Find the electric field at a point. on the axis of the ring at a distance x from the centre.
A circular wire loop of radius R carries a total charge q distributed uniformly over its length. A small length x (ltlt R) of the wire is cut off. Find the electric field at the centre due to the remaining wire.
A thin disc of radius R has charge Q distributed uniformly on its surface. The disc is rotated about one of its diametric axis with angular velocity omega . The magnetic moment of the arrangement is
A thin circular wire of radius r has a charge Q. If a point charge q is placed at the centre of the ring, then find the increase in tension in the wire.
As shown in figure there is a ring having radius R and charge q distributed uniformly over it. If ring is rotated with a constant angular velocity @, then torque acting on the ring due to magnetic force is (Assume that magnetic field B is parallel to plane of ring)
A non-conducting ring of radius R has charge Q distributed unevenly over it. If it rotates with an angular velocity omega the equivalent current will be:
JEE MAINS PREVIOUS YEAR ENGLISH-JEE MAINS-Chemistry
