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Two conductors have the same resistance ...

Two conductors have the same resistance at `0^@C` but their temperature coefficient of resistanc are `alpha_1 and alpha_2`. The respective temperature coefficients of their series and parallel combinations are nearly

A

`(alpha_(1)+alpha_(2))/(2),alpha_(1)+alpha_(2)`

B

`alpha_(1)+alpha_(2),(alpha_(1)+alpha_(2))/(2)`

C

`alpha_(1)+alpha_(2),(alpha_(1)+alpha_(2))/(alpha_(1)+alpha_(2))`

D

`(alpha_(1)+alpha_(2))/(2),(alpha_(1)+alpha_(2))/(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the temperature coefficients of resistance for two conductors when they are connected in series and parallel. The conductors have the same resistance at 0°C but different temperature coefficients of resistance, denoted as α₁ and α₂. ### Step-by-Step Solution: 1. **Understanding Resistance and Temperature Coefficient**: The resistance \( R \) of a conductor at a temperature \( T \) is given by the formula: \[ R(T) = R_0 (1 + \alpha T) \] where \( R_0 \) is the resistance at 0°C, and \( \alpha \) is the temperature coefficient of resistance. 2. **Resistance in Series**: For two resistors \( R_1 \) and \( R_2 \) connected in series, the total resistance \( R_s \) at temperature \( T \) is: \[ R_s(T) = R_1(T) + R_2(T) \] Substituting the resistance formula: \[ R_s(T) = R_0(1 + \alpha_1 T) + R_0(1 + \alpha_2 T) \] Simplifying this: \[ R_s(T) = R_0(2 + (\alpha_1 + \alpha_2) T) \] The temperature coefficient of resistance for the series combination \( \alpha_s \) is given by: \[ \alpha_s = \frac{\alpha_1 + \alpha_2}{2} \] 3. **Resistance in Parallel**: For two resistors \( R_1 \) and \( R_2 \) connected in parallel, the equivalent resistance \( R_p \) at temperature \( T \) is: \[ \frac{1}{R_p(T)} = \frac{1}{R_1(T)} + \frac{1}{R_2(T)} \] Substituting the resistance formula: \[ \frac{1}{R_p(T)} = \frac{1}{R_0(1 + \alpha_1 T)} + \frac{1}{R_0(1 + \alpha_2 T)} \] Simplifying this: \[ \frac{1}{R_p(T)} = \frac{(1 + \alpha_2 T) + (1 + \alpha_1 T)}{R_0(1 + \alpha_1 T)(1 + \alpha_2 T)} \] \[ = \frac{2 + (\alpha_1 + \alpha_2) T}{R_0(1 + \alpha_1 T)(1 + \alpha_2 T)} \] For small \( \alpha_1 \) and \( \alpha_2 \), we can approximate: \[ R_p(T) \approx \frac{R_0}{2} (1 + \frac{\alpha_1 + \alpha_2}{2} T) \] The temperature coefficient of resistance for the parallel combination \( \alpha_p \) is: \[ \alpha_p = \frac{\alpha_1 + \alpha_2}{2} \] 4. **Final Results**: - The temperature coefficient of resistance for the series combination is: \[ \alpha_s = \frac{\alpha_1 + \alpha_2}{2} \] - The temperature coefficient of resistance for the parallel combination is: \[ \alpha_p = \frac{\alpha_1 + \alpha_2}{2} \] ### Conclusion: Thus, the respective temperature coefficients of resistance for the series and parallel combinations are both approximately \( \frac{\alpha_1 + \alpha_2}{2} \).
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