Home
Class 12
CHEMISTRY
Which of the following compounds will no...

Which of the following compounds will not undergo Friedel`-` Crafts reaction easily ?

A

B

C

D

Text Solution

AI Generated Solution

The correct Answer is:
To determine which compound will not undergo Friedel-Crafts reaction easily, we first need to understand the mechanism and stability of the intermediates formed during the reaction. The Friedel-Crafts reaction can be either alkylation or acylation, and it involves the formation of carbocations. ### Step-by-Step Solution: 1. **Identify the Compounds**: We have several compounds to analyze. Let's denote them as: - Option A: Vinyl chloride (C2H3Cl) - Option B: Allylic chloride (C3H5Cl) - Option C: Carbonyl compound (e.g., CH3COCl) - Option D: Another carbonyl compound (e.g., C6H5COCl) 2. **Understand Friedel-Crafts Mechanism**: - Friedel-Crafts alkylation involves the formation of a carbocation from an alkyl halide in the presence of a Lewis acid (like AlCl3). - Friedel-Crafts acylation involves the formation of an acylenium ion from an acyl halide in the presence of a Lewis acid. 3. **Analyze Stability of Carbocations**: - **Vinyl Cation**: The vinyl cation (formed from vinyl chloride) is less stable because it is sp2 hybridized and has no resonance stabilization. - **Allylic Cation**: The allylic cation (formed from allylic chloride) is more stable due to resonance stabilization. - **Acylenium Ion**: The acylenium ion (from acyl halides) is stabilized by resonance and backbonding, making it stable. 4. **Evaluate Each Option**: - **Option A (Vinyl Chloride)**: Forms a vinyl cation, which is unstable and does not favor the Friedel-Crafts reaction. - **Option B (Allylic Chloride)**: Forms an allylic cation, which is stable and can undergo Friedel-Crafts reaction. - **Option C (Carbonyl Compound)**: Forms a stable acylenium ion, which can undergo Friedel-Crafts acylation. - **Option D (Another Carbonyl Compound)**: Similar to Option C, it forms a stable acylenium ion. 5. **Conclusion**: Based on the stability of the carbocations formed, **Vinyl Chloride (Option A)** will not undergo the Friedel-Crafts reaction easily due to the instability of the vinyl cation. ### Final Answer: **Vinyl chloride will not undergo Friedel-Crafts reaction easily.**
Promotional Banner

Topper's Solved these Questions

  • JEE MAINS

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise QUESTION|1 Videos
  • JEE MAIN

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise CHEMISTRY|146 Videos
  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise CHEMSITRY|23 Videos

Similar Questions

Explore conceptually related problems

Which of the following compounds will not undergo Friedel Craft's reaction with benzene ?

Friedel - Crafts acylation

Which of the following compounds do not give Friedel Crafts reaction?

Which of the follwing compounds will undergo Friedel Creadfts alylation with faster rate?

Friedel - Crafts alkylation