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An observer is moving with half the spee...

An observer is moving with half the speed of light towards a stationary microwave source emitting waves at frequency 10 GhHz. What is the frequency of the microwave measured by the observer? (speed of light=`3xx10^(8)ms`)

A

`"tan"^(-1)("sin" theta_(c))`

B

`(1)/("tan"^(-1) ("sin"theta_(c)))`

C

`"cos"^(-1) ("sin"theta_(c))`

D

`(1)/("cos"^(-1)("sin"theta_(c)))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the frequency of the microwave measured by an observer moving towards a stationary microwave source, we can use the relativistic Doppler effect formula. Here’s the step-by-step solution: ### Step 1: Identify the given values - Frequency of the source (f₀) = 10 GHz = \(10 \times 10^9\) Hz - Speed of light (c) = \(3 \times 10^8\) m/s - Speed of the observer (v) = \(c/2 = \frac{3 \times 10^8}{2} = 1.5 \times 10^8\) m/s ### Step 2: Use the relativistic Doppler effect formula The formula for the apparent frequency (f') when the observer is moving towards a stationary source is given by: \[ f' = f_0 \sqrt{\frac{c + v}{c - v}} \] ### Step 3: Substitute the values into the formula Now we can substitute the values into the formula: \[ f' = 10 \times 10^9 \sqrt{\frac{3 \times 10^8 + 1.5 \times 10^8}{3 \times 10^8 - 1.5 \times 10^8}} \] ### Step 4: Simplify the expression inside the square root Calculating the numerator and denominator: - Numerator: \(3 \times 10^8 + 1.5 \times 10^8 = 4.5 \times 10^8\) - Denominator: \(3 \times 10^8 - 1.5 \times 10^8 = 1.5 \times 10^8\) So we have: \[ f' = 10 \times 10^9 \sqrt{\frac{4.5 \times 10^8}{1.5 \times 10^8}} \] ### Step 5: Simplify the fraction The fraction simplifies to: \[ \frac{4.5 \times 10^8}{1.5 \times 10^8} = 3 \] Thus, we can rewrite the equation: \[ f' = 10 \times 10^9 \sqrt{3} \] ### Step 6: Calculate the square root and the final frequency Now, we know that \(\sqrt{3} \approx 1.732\): \[ f' = 10 \times 10^9 \times 1.732 = 17.32 \times 10^9 \text{ Hz} \] Converting this back to GHz: \[ f' \approx 17.32 \text{ GHz} \] ### Final Answer The frequency of the microwave measured by the observer is approximately **17.32 GHz**. ---
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