When chlorine reacts with cold and dilute solution of sodium hydroxide, the products obtained are

Options

A. Cl− + ClO−
B. `BrF_(5)`
C. `PF_(5)`
D. `[CrF_(6)]^(3-)`

Answer

To determine the products formed when chlorine reacts with a cold and dilute solution of sodium hydroxide (NaOH), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are chlorine gas (Cl₂) and sodium hydroxide (NaOH). The sodium hydroxide solution is specified to be cold and dilute.

2. **Understand the Reaction Conditions**:
Chlorine acts as an oxidizing agent, and when it reacts with a strong base like NaOH, it can undergo a reaction that produces hypochlorite ions.

3. **Write the Balanced Chemical Equation**:
The balanced chemical equation for the reaction of chlorine with cold and dilute sodium hydroxide is:
\[ Cl_2 + 2 NaOH \rightarrow NaCl + NaClO + H_2O \]
Here, sodium chloride (NaCl), sodium hypochlorite (NaClO), and water (H₂O) are produced.

4. **Identify the Products**:
From the balanced equation, we can see that the products formed are:
- Sodium Chloride (NaCl)
- Sodium Hypochlorite (NaClO)
- Water (H₂O)

5. **Conclusion**:
Therefore, the products obtained when chlorine reacts with a cold and dilute solution of sodium hydroxide are sodium chloride (NaCl), sodium hypochlorite (NaClO), and water (H₂O).

### Final Answer:
The products obtained are:
- Sodium Chloride (NaCl)
- Sodium Hypochlorite (NaClO)
- Water (H₂O)