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Given magnetic field equation isB= 3xx1...

Given magnetic field equation is`B= 3xx10^(-8) sin (omega t +kx +phi)hatj`then appropriate equation for electric field (E) will be :

A

`20xx10^(-9) sin (omega t +kx +phi ) hatk`

B

`9 sin ( omega t +kx + phi ) hatk`

C

` 16xx10^(-9) sin (omega t+ kx +phi)hatk`

D

`3xx10^(-9)siin (omega t +kx +phi)hatk`

Text Solution

AI Generated Solution

The correct Answer is:
To find the appropriate equation for the electric field (E) given the magnetic field equation \( B = 3 \times 10^{-8} \sin(\omega t + kx + \phi) \hat{j} \), we can follow these steps: ### Step 1: Identify the given magnetic field parameters The given magnetic field \( B \) is expressed as: \[ B = B_0 \sin(\omega t + kx + \phi) \hat{j} \] where \( B_0 = 3 \times 10^{-8} \) T (Tesla). ### Step 2: Use the relationship between electric field and magnetic field In electromagnetic waves, the relationship between the magnitudes of the electric field \( E_0 \) and the magnetic field \( B_0 \) is given by: \[ \frac{E_0}{B_0} = c \] where \( c \) is the speed of light in vacuum, approximately \( 3 \times 10^8 \) m/s. ### Step 3: Calculate the magnitude of the electric field Rearranging the equation gives us: \[ E_0 = B_0 \cdot c \] Substituting the values we have: \[ E_0 = (3 \times 10^{-8}) \cdot (3 \times 10^8) \] Calculating this gives: \[ E_0 = 9 \, \text{N/C} \] ### Step 4: Determine the direction of the electric field The magnetic field is in the \( \hat{j} \) direction (y-direction). In electromagnetic waves, the electric field \( E \), magnetic field \( B \), and the direction of propagation are mutually perpendicular. If the magnetic field is in the \( \hat{j} \) direction, the electric field will be in the \( \hat{k} \) direction (z-direction). ### Step 5: Write the electric field equation Thus, the electric field can be expressed as: \[ E = E_0 \sin(\omega t + kx + \phi) \hat{k} \] Substituting \( E_0 = 9 \) N/C, we get: \[ E = 9 \sin(\omega t + kx + \phi) \hat{k} \] ### Final Answer The appropriate equation for the electric field \( E \) is: \[ E = 9 \sin(\omega t + kx + \phi) \hat{k} \] ---
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